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Shell Programming and Scripting
Snytax error on If Statement--help
Post 302192792 by dannyd_y on Wednesday 7th of May 2008 09:58:29 PM
05-07-2008
Snytax error on If Statement--help
year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`
case $month in
1 | 3 | 5 | 7 | 8 | 10 | 12);;
if($day =7 ); then
$day=6
fi
4 | 6 | 9 | 11);;
if [ $day = 0 ] ; then
$day=31
fi
2);;
if [ $day = 0 ] ; then
if [ `expr $year % 4` -eq 0]; then
$day = 28
else
$day = 29
fi
fi
*) echo error: too many arguments 1>&2 ;;
esac
DATE=$year$month$day
cp $HOME/*$DATE*.log $HOME/QVGLog
cd $HOME/QVGLog
gzip *
the error message is
./call: line 9: syntax error near unexpected token `('
./call: line 9: `if($day =7 ); then'
Pls help, i've checked the syntax for if else statement on web, but cant fix it.
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`
case $month in
1 | 3 | 5 | 7 | 8 | 10 | 12);;
if($day =7 ); then
$day=6
fi
4 | 6 | 9 | 11);;
if [ $day = 0 ] ; then
$day=31
fi
2);;
if [ $day = 0 ] ; then
if [ `expr $year % 4` -eq 0]; then
$day = 28
else
$day = 29
fi
fi
*) echo error: too many arguments 1>&2 ;;
esac
DATE=$year$month$day
cp $HOME/*$DATE*.log $HOME/QVGLog
cd $HOME/QVGLog
gzip *
the error message is
./call: line 9: syntax error near unexpected token `('
./call: line 9: `if($day =7 ); then'
Pls help, i've checked the syntax for if else statement on web, but cant fix it.
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LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3) cal_from_jd - Converts from Julian Day Count to a supported calendar SYNOPSIS
array cal_from_jd (int $jd, int $calendar) DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $jd - Julian day as integer o $calendar - Calendar to convert to RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and the date in string form "month/day/year". EXAMPLES
Example #1 cal_from_jd(3) example <?php $today = unixtojd(mktime(0, 0, 0, 8, 16, 2003)); print_r(cal_from_jd($today, CAL_GREGORIAN)); ?> The above example will output: Array ( [date] => 8/16/2003 [month] => 8 [day] => 16 [year] => 2003 [dow] => 6 [abbrevdayname] => Sat [dayname] => Saturday [abbrevmonth] => Aug [monthname] => August ) SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3). PHP Documentation Group CAL_FROM_JD(3)