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Shell Programming and Scripting
awk arguments
Post 302192427 by Annihilannic on Tuesday 6th of May 2008 11:33:27 PM
05-07-2008
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p080$
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I have an awk script where I pass some arguments
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# more minusf.awk
#!/bin/awk -f
BEGIN {
FS=":";
}
{
if ( $2 == "" ) {
print $1 ": no password!";
}
}
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svcdumplog - Prints contents of a binary serviceability log file SYNOPSIS
svcdumplog [-s num_of_entries] logfile OPTIONS
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