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Top Forums Shell Programming and Scripting escaping double-quotes inside the script? Post 302191907 by GKnight on Monday 5th of May 2008 10:54:11 AM
Old 05-05-2008
escaping double-quotes inside the script?

I'm having a strange problem with escaping double-quotes. I have a script that looks like this:

Code:
#!/bin/bash

[snip]

for HOST in `cat $INFILE | grep -v ^#`
do

        for VFILER in `some_command`
        do
                echo " "
                echo -e '\E[32;40m' "  **************** VFiler $VFILER on $HOST ***************"; tput sgr0
                ssh $HOST "vfiler run $VFILER "$COMMAND""
                echo " "
                echo " "
        done
done

The problem with ssh command is that it needs to enclose the actual command in double quotes, i.e. this will execute correctly:

Code:
ssh nas01a "vfiler run fs03n cifs shares -change * -novscanread"

but this will return an error:

Code:
ssh nas01a vfiler run fs03n cifs shares -change * -novscanread

In other words, I need to enclose the contents of the ssh command in double-quotes. How can I do it in the script? The way it is above, the quotes are not passed to the ssh command. This doesn't work:

Code:
ssh $HOST \""vfiler run $VFILER "$COMMAND""\"

What am I doing wrong?
 

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