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Shell Programming and Scripting
Calender Unix programming date issues
Post 302191319 by Vicky Narayan on Friday 2nd of May 2008 07:27:22 AM
05-02-2008
Buddy,
The code seems to be correct. But it needs certain modifications at some places. Please find below the corrected code:
year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`
case $month in
1 | 3 | 5 | 7 | 8 | 9 | 10 | 12);;
if [ $day = 0 ]; then
day=32
day1=`expr $day-1`
fi
4 | 6 | 11);;
if [ $day = 0 ]; then
day=31
day1=`expr $day-1`
fi
2);;
if [ `expr $month % 4` -eq 0]; then
if[ $day = 0 ]; then
day = 30
day1 =`expr $day-1`
fi
else
if[ $day = 0 ]; then
day = 29
day1 =`expr $day-1`
fi
fi
*) echo error: too many arguments 1>&2 ;;
esac
DATE=$year$month$day1
mv $HOME/*$DATE*log $HOME/archive
cd $HOME/archive
gzip *
Probably this would work. Just check out the differences with your code. Revert back in case of any issue.
The code seems to be correct. But it needs certain modifications at some places. Please find below the corrected code:
year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`
case $month in
1 | 3 | 5 | 7 | 8 | 9 | 10 | 12);;
if [ $day = 0 ]; then
day=32
day1=`expr $day-1`
fi
4 | 6 | 11);;
if [ $day = 0 ]; then
day=31
day1=`expr $day-1`
fi
2);;
if [ `expr $month % 4` -eq 0]; then
if[ $day = 0 ]; then
day = 30
day1 =`expr $day-1`
fi
else
if[ $day = 0 ]; then
day = 29
day1 =`expr $day-1`
fi
fi
*) echo error: too many arguments 1>&2 ;;
esac
DATE=$year$month$day1
mv $HOME/*$DATE*log $HOME/archive
cd $HOME/archive
gzip *
Probably this would work. Just check out the differences with your code. Revert back in case of any issue.
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LEARN ABOUT MINIX
holidays
holidays(4) File Formats holidays(4) NAME
holidays - prime/nonprime table for the accounting system SYNOPSIS
/etc/acct/holidays DESCRIPTION
The /etc/acct/holidays file describes which hours are considered prime time and which days are holidays. Holidays and weekends are con- sidered non-prime time hours. /etc/acct/holidays is used by the accounting system. All lines beginning with an "*" are comments. The /etc/acct/holidays file consists of two sections. The first non-comment line defines the current year and the start time of prime and non-prime time hours, in the form: current_year prime_start non_prime_start The remaining non-comment lines define the holidays in the form: month/day company_holiday Of these two fields, only the month/day is actually used by the accounting system programs. The /etc/acct/holidays file must be updated each year. EXAMPLES
Example 1: Example of the /etc/acct/holidays file. The following is an example of the /etc/acct/holidays file: * Prime/Nonprime Table for the accounting system * * Curr Prime Non-Prime * Year Start Start * 1991 0830 1800 * * only the first column (month/day) is significant. * * month/day Company Holiday * 1/1 New Years Day 5/30 Memorial Day 7/4 Indep. Day 9/5 Labor Day 11/24 Thanksgiving Day 11/25 day after Thanksgiving 12/25 Christmas 12/26 day after Christmas SEE ALSO
acct(1M) SunOS 5.10 28 Mar 1991 holidays(4)