Hi all,
Have the following code(1) producing the results(2 & 3).
Would like to know if there is a way to format the two reports created in a similar fashion.
IE - The first is formatted nicely as a result of the echo "$xmpbdate $xavgs" >> $xmpbrpt
However when I attempt to do the same on... (7 Replies)
Hi need some advice..
#grep -i hostname test.csv
(gives the below output)
HOSTNAME,name,host_test,,,,,,,,
Now I need to format the above output as below.
HOSTNAME:
name=host_test
Any easy way of doing this using awk or sed or printf? (4 Replies)
Ok, for a fun project, my goal is to replicate the style of "catalog" on an old apple ]
*A 002 SOMEAPPLESOFTFILE
B 004 SOMEFILE
T 006 SOMETEXT
I 002 SOMEINTEGERFILE
The first character is either " " or "*" depending on if the file is locked or not.
Next is the filetype, so in... (1 Reply)
I am using find and ls to search for "warez" files on my server.
find /home/ -regex ".*\.\(avi\|mp3\|mpeg\|mpg\|iso\)" -print0 | xargs -0 ls -oh
This command produces this:
-rw-r--r-- 1 1000 3.2M Feb 18 2009 /home/user/public_html/lupus.mp3
I want to only get this
3.2M... (4 Replies)
Sorry for being a n00b, but I'm having a lot more trouble than I should with formatting the output to the program I finally completed. I'm basically looking for the linux equivalent to setw( ) from c++ so that I can print things in columns like this (but without the underlines lol):
MISSPELLED: ... (4 Replies)
Hi Experts,
I have to create a report for certain audit and my output looks as follows
I m trying to format my output to look like
Any inputs would be highly appreciated
Thanks
Syed (5 Replies)
Hi Guys
I need help removing some lines from output i am receiving from a shell script.
Here is the output:
http://i52.tinypic.com/10z0fut.png
I am trying to remove the output that i have circled.
. ${EDW}/extracts/bin/extracts_setup2.sh
. ${EDW}/extracts/extracts.conf
... (7 Replies)
Hi,
I have a file which contents entries in this form.
Only in /data4/temp abc.000001
Only in /data4/temp abc.000003
Only in /data4/temp abc.000012
Only in /data4/temp abc.000120
Only in /data4/temp abc.000133
Only in /data4/temp abc.001444
i want to read line by line and format... (2 Replies)
I am using FORTRAN 90 on AIX 5.3 and need to output my data to a tab-delimited file. It must have actual tabs, and I cannot figure out a way to make it work. The resulting file will be imported into another application (quickbooks) as an .iif file....for some reason, it needs the tabs; spaces do... (2 Replies)
Hi,
I am trying to use printf command and format certain output in a specific format as under:
While the left side (upto |) of the above format is part of a fixed header function, the right side is where i am expecting data to be printed. However, as seen, Row1 value is reflecting on last... (5 Replies)
Discussion started by: EmbedUX
5 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)