05-01-2008
Formatting Output
Hi
I tried running the below
awk 'BEGIN { printf ("%s %-51s %s %-7s %s",$var1,$var2,$var3,$var4,$var5)}'
from the command prompt and it is not working.
Getting the error
awk: Field $() is not correct.
The source line number is 1.
Actually my requirement is to form a string based on a particular format.
The format i have mentiioned above.
But in UNIX script i am not able to do the formatting.
Let me know if you have any clues.
Regards
Dhanamurthy
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LEARN ABOUT LINUX
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)
NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO
shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)