04-30-2008
I would do it with a grep of the login_id in /etc/password
grep $login_id | awk '{print $5, $6}'
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hi
I am try to run following script using c-shell but i get the following syntex error:-
----script---
---------------------------------------------------------------------------------
#!/bin/csh
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echo "
1) system paging
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Hi ,
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i=1
out=""
j=`expr 2 * $1`
while
do
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((i=i+1))
done
while
do
print ${out%?}
((i=i+1))
done
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expr: 0402-050 Syntax error.
# (6 Replies)
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Hi,
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LEARN ABOUT NETBSD
zfgrep
ZGREP(1) BSD General Commands Manual ZGREP(1)
NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files
SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...]
zegrep [grep-flags] [--] pattern [file ...]
zfgrep [grep-flags] [--] pattern [file ...]
DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).
The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern
argument.
zegrep calls egrep(1), while zfgrep calls fgrep(1).
EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.
SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)
AUTHORS
Thomas Klausner <wiz@NetBSD.org>
BSD
December 28, 2003 BSD