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Top Forums Shell Programming and Scripting printing each users by processes Post 302190051 by sam4now on Monday 28th of April 2008 02:51:46 PM
Old 04-28-2008
printing each users by processes

hello All,

i am trying to get the each users by with thier processing. I have try it in several ways but i am not getting thier my code is

#!bin/bash/
users=`cat /etc/passwd | cut -d':' -f5`
onlineusers=`users | tr '.' ' '`
$onlineusers | while read `$users`
do
echo `ps -U $users`
done

but its not working, root: it says command not found

pls any way around it.
 

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partimaged-passwd(8)				       Partition Image Server Configuration				      partimaged-passwd(8)

NAME
partimaged-passwd - Manage partimaged user accounts SYNTAX
partimaged-passwd [-Dhl] username password partimaged-passwd [-Dhl] username DESCRIPTION
partimaged can either authenticate against local user accounts (This needs access to /etc/shadow. As this is a potential security risk this method is not recommended) or its own password database in /etc/partimaged/passwd.db. To simplify the management of the partimaged user database this tool was written. It allows to easily add and remove users or list the users in the database. All users in this database are allowed to access the partimaged server. OPTIONS
-D username Delete the specified user from the password file. -l List users in password file and exit. -h Output help information and exit. FILES
/etc/partimaged/passwd.db AUTHORS
Michael Biebl <biebl@debian.org> SEE ALSO
partimaged(8), partimagedusers(5), partimage(1) Michael Biebl <;biebl@teco.edu> 0.1 partimaged-passwd(8)
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