04-28-2008
How print number
Hi,
I am using for loop as follow:
for n in `ls`
do
echo "$n"
done
The code is running fine and aI am getting valid output as:
jick
zenny
assi
yogi
But 1also want to print count in front of each output like this:
1 jick
2 zenny
3 assi
4 yogi
What should I add in my logic for achiving this?
Kinly advise.
Regards,
Yogi
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ECHO(1) BSD General Commands Manual ECHO(1)
NAME
echo -- write arguments to the standard output
SYNOPSIS
echo [-n] [string ...]
DESCRIPTION
The echo utility writes any specified operands, separated by single blank (' ') characters and followed by a newline ('
') character, to the
standard output.
The following option is available:
-n Do not print the trailing newline character. This may also be achieved by appending 'c' to the end of the string, as is done by iBCS2
compatible systems. Note that this option as well as the effect of 'c' are implementation-defined in IEEE Std 1003.1-2001
(``POSIX.1'') as amended by Cor. 1-2002. Applications aiming for maximum portability are strongly encouraged to use printf(1) to sup-
press the newline character.
Some shells may provide a builtin echo command which is similar or identical to this utility. Most notably, the builtin echo in sh(1) does
not accept the -n option. Consult the builtin(1) manual page.
EXIT STATUS
The echo utility exits 0 on success, and >0 if an error occurs.
SEE ALSO
builtin(1), csh(1), printf(1), sh(1)
STANDARDS
The echo utility conforms to IEEE Std 1003.1-2001 (``POSIX.1'') as amended by Cor. 1-2002.
BSD
April 12, 2003 BSD