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Top Forums UNIX for Dummies Questions & Answers extracting date from a filename Post 302188358 by bakunin on Wednesday 23rd of April 2008 08:47:31 AM
Old 04-23-2008
Quote:
Originally Posted by era
This requires a version of date which can do -d "day" and +%s which -- with my luck -- probably excludes yours.
You can do date arithmetics even if the date command doesn't support it - at least on the day level - quite easily using the TZ variable (i suppose in the following example that you are in the GMT timezone. You will have to introduce a corrective factor if not.):

Code:
# print - "yesterdays date: $(TZ=GMT+24; date)"
# print - "one week ago: $(TZ=GMT+$(( 24*7 )); date)"

bakunin
 

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CHGRP(3)								 1								  CHGRP(3)

chgrp - Changes file group

SYNOPSIS
bool chgrp (string $filename, mixed $group) DESCRIPTION
Attempts to change the group of the file $filename to $group. Only the superuser may change the group of a file arbitrarily; other users may change the group of a file to any group of which that user is a member. PARAMETERS
o $filename - Path to the file. o $group - A group name or number. RETURN VALUES
Returns TRUE on success or FALSE on failure. EXAMPLES
Example #1 Changing a file's group <?php $filename = 'shared_file.txt'; $format = "%s's Group ID @ %s: %d "; printf($format, $filename, date('r'), filegroup($filename)); chgrp($filename, 8); clearstatcache(); // do not cache filegroup() results printf($format, $filename, date('r'), filegroup($filename)); ?> NOTES
Note This function will not work on remote files as the file to be examined must be accessible via the server's filesystem. Note When safe mode is enabled, PHP checks whether the files or directories being operated upon have the same UID (owner) as the script that is being executed. SEE ALSO
chown(3), chmod(3). PHP Documentation Group CHGRP(3)
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