This requires a version of date which can do -d "day" and +%s which -- with my luck -- probably excludes yours.
You can do date arithmetics even if the date command doesn't support it - at least on the day level - quite easily using the TZ variable (i suppose in the following example that you are in the GMT timezone. You will have to introduce a corrective factor if not.):
Hi,
I have a requirement that i need to store only the filename without its extension. Can anyone please help me to do this.
For Example, i have stored the filename in a varialble called fname. I need to extract all the charecters before the first occurence of the dot.
If fname has value... (3 Replies)
Hi,
Any help on this would be very appreciated.
I capture the full path & filename in a variable like (varFile=/home/user/extfile.txt). Now in my shell script I have to use only the filename part i.e. extfile.txt. How do I extract only the filename part from the variable?
Thanks in... (3 Replies)
I need to extract the date part from the file name (20080221 in this ex) and compare it with the current date and delete it, if it is a past date.
$file = exp_ABCD4_T-2584780_upto_20080221.dmp.Z
really appreciate any help.
thanks
mkneni (4 Replies)
Hi,
I need to extract the file name without filetype.
Suppose in DIR1 if i have files like F1.txt and F2.DOC then i need to return F1 and F2 only with out file types (txt and DOC).
I tried with the following code
newname = ` $i | cut -d "'." -f1`
but it is giving the error " 0403-006... (1 Reply)
hi all,
I'm trying to automate some tasks and while I've got the script itself working, I'm having difficulties with automatic file detection and associated variable setting...
for example, in a directory I've got several files... something along the lines of:
xis0_NAME_src.file... (2 Replies)
I am using ksh93 on Solaris.
Ok, this may seem like a simple request at first. I have a directory that contains sets of files with a YYYYMMDD component to the name, along with other files of different filespecs. something like this:
20110501_1.dat
20110501_2.dat
20110501_3.dat... (2 Replies)
Hi
I would like to extract the first portion of filename from a list of files.
The filename pattern is of the form 123456789_TEXT_TEXT_TEXT_.csv. I want to extract just the numerical portion of this filename from the list of files and then output this into another text file.
K (6 Replies)
Hello,
I'd like to write a monthly archive script that archives some logs. But I'd like to do it based on yesterday's date. In other words, I'd like to schedule the script to run on the 1st day of each month, but have the archive filename include the previous month instead.
Here's what I... (5 Replies)
Suppose i have a list of files in a directory as mentioned below
1. Shankar_04152019_ny.txt
2. Gopi_shan_03122019_mi.txt
3. Siva_mourya_02242019_nd.txt
..
.
.
.
.
1000 . Jiva_surya_02282019_nd.txt
query : At one shot i want to modify the above all filenames present in one path with... (4 Replies)
I am using bash and have a filename with a path and extension and want to extract just the filename
Have used the following code, oflna gives the file name with extension, but now neet to remove the .texi at the end.
oflna=${flnm##*/}
oflnb=${${flnm##*/}%.*}
echo "flnm: $flnm"
echo... (1 Reply)
Discussion started by: Danette
1 Replies
LEARN ABOUT PHP
chgrp
CHGRP(3) 1 CHGRP(3)chgrp - Changes file groupSYNOPSIS
bool chgrp (string $filename, mixed $group)
DESCRIPTION
Attempts to change the group of the file $filename to $group.
Only the superuser may change the group of a file arbitrarily; other users may change the group of a file to any group of which that user
is a member.
PARAMETERS
o $filename
- Path to the file.
o $group
- A group name or number.
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
Changing a file's group
<?php
$filename = 'shared_file.txt';
$format = "%s's Group ID @ %s: %d
";
printf($format, $filename, date('r'), filegroup($filename));
chgrp($filename, 8);
clearstatcache(); // do not cache filegroup() results
printf($format, $filename, date('r'), filegroup($filename));
?>
NOTES
Note
This function will not work on remote files as the file to be examined must be accessible via the server's filesystem.
Note
When safe mode is enabled, PHP checks whether the files or directories being operated upon have the same UID (owner) as the script
that is being executed.
SEE ALSO chown(3), chmod(3).
PHP Documentation Group CHGRP(3)