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Shell Programming and Scripting
Trying to kill a program via help command.
Post 302187782 by TiznaraN on Tuesday 22nd of April 2008 03:29:43 AM
04-22-2008
-aux errors for me, here's what I have now
ps | awk ' /program/ {print $1} '
This is outputting the PID, isn't there a way to store the number in a variable rather than print it, maybe then pipe it into a kill? I'm not sure of the syntax I guess.
edit: I meant to say via exit command in the title.
edit2: no longer relevant
edit3: break; I gotta start dumbing myself down, or reading more before trying to code.
But, pretend this was to do something other than break a loop., Let's say I am trying to find out how many times someone has logged into the machine. Use last to display all the different logins, several names pop up, some multiple times. This is something else I was working on, all I can figure out is the total number of logins, but I can't determine how to compare if $1(user name) is there more than once, and ontop of that count it if it is.
ex.
toyoung
rasmith
toyoung
output i'm looking for would be
toyoung 2
rasmith 1
here's what i have:
last | awk ' END {print "Number of logins:", NR} '
ps | awk ' /program/ {print $1} '
This is outputting the PID, isn't there a way to store the number in a variable rather than print it, maybe then pipe it into a kill? I'm not sure of the syntax I guess.
edit: I meant to say via exit command in the title.
edit2: no longer relevant
edit3: break; I gotta start dumbing myself down, or reading more before trying to code.
But, pretend this was to do something other than break a loop., Let's say I am trying to find out how many times someone has logged into the machine. Use last to display all the different logins, several names pop up, some multiple times. This is something else I was working on, all I can figure out is the total number of logins, but I can't determine how to compare if $1(user name) is there more than once, and ontop of that count it if it is.
ex.
toyoung
rasmith
toyoung
output i'm looking for would be
toyoung 2
rasmith 1
here's what i have:
last | awk ' END {print "Number of logins:", NR} '
Last edited by TiznaraN; 04-22-2008 at 04:57 AM..
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LEARN ABOUT SUNOS
listusers
listusers(1) User Commands listusers(1) NAME
listusers - list user login information SYNOPSIS
listusers [-g groups] [-l logins] DESCRIPTION
Executed without any options, this command lists all user logins sorted by login. The output shows the login ID and the account field value from the system's password database as specified by /etc/nsswitch.conf. OPTIONS
The following options are supported: -g groups Lists all user logins belonging to group, sorted by login. Multiple groups can be specified as a comma-separated list. -l logins Lists the user login or logins specified by logins, sorted by login. Multiple logins can be specified as a comma-separated list. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | |Availability |SUNWcsu | +-----------------------------+-----------------------------+ SEE ALSO
nsswitch.conf(4), attributes(5) NOTES
A user login is one that has a UID of 100 or greater. The -l and -g options can be combined. User logins will only be listed once, even if they belong to more than one of the selected groups. SunOS 5.10 18 Mar 1994 listusers(1)