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Top Forums Shell Programming and Scripting comparing scalars contaning "DOUBLE QUOTES" as data Post 302187214 by era on Sunday 20th of April 2008 08:09:40 AM
Old 04-20-2008
First of all, you need to learn to quote arguments properly. Simply double-quote anything with a variable in it, and you should be fine, most of the time.

If the strings also contain regex specials (in this case, asterisks), those need to be escaped somehow, or you need to use a different comparison function. May I suggest the plain old case statement?

Code:
case $A in *"$B"*) echo "$A contains $B";; *) echo does not;; esac


Last edited by era; 04-20-2008 at 09:12 AM.. Reason: Had $A and $B mixed up
 

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IN_ARRAY(3)								 1							       IN_ARRAY(3)

in_array - Checks if a value exists in an array

SYNOPSIS
bool in_array FALSE (mixed $needle, array $haystack, [bool $strict]) DESCRIPTION
Searches $haystack for $needle using loose comparison unless $strict is set. PARAMETERS
o $needle - The searched value. Note If $needle is a string, the comparison is done in a case-sensitive manner. o $haystack - The array. o $strict - If the third parameter $strict is set to TRUE then the in_array(3) function will also check the types of the $needle in the $haystack. RETURN VALUES
Returns TRUE if $needle is found in the array, FALSE otherwise. EXAMPLES
Example #1 in_array(3) example <?php $os = array("Mac", "NT", "Irix", "Linux"); if (in_array("Irix", $os)) { echo "Got Irix"; } if (in_array("mac", $os)) { echo "Got mac"; } ?> The second condition fails because in_array(3) is case-sensitive, so the program above will display: Got Irix Example #2 in_array(3) with strict example <?php $a = array('1.10', 12.4, 1.13); if (in_array('12.4', $a, true)) { echo "'12.4' found with strict check "; } if (in_array(1.13, $a, true)) { echo "1.13 found with strict check "; } ?> The above example will output: 1.13 found with strict check Example #3 in_array(3) with an array as needle <?php $a = array(array('p', 'h'), array('p', 'r'), 'o'); if (in_array(array('p', 'h'), $a)) { echo "'ph' was found "; } if (in_array(array('f', 'i'), $a)) { echo "'fi' was found "; } if (in_array('o', $a)) { echo "'o' was found "; } ?> The above example will output: 'o' was found SEE ALSO
array_search(3), isset(3), array_key_exists(3). PHP Documentation Group IN_ARRAY(3)
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