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Full Discussion: egrep help
Top Forums Shell Programming and Scripting egrep help Post 302186756 by era on Friday 18th of April 2008 02:34:13 AM
Old 04-18-2008
That's what grep does; you need to construct a regular expression which indicates which part of the line to match if you don't want to match anywhere in the line. It can't magically guess which part of the line you want the match to be in.

If you don't want to spend too much time on learning this stuff, there's a lot of log grepping tools out there, but it's also easy to roll your own.

awk is probably easier to approach, but this is perfectly doable in egrep, too.

Code:
egrep -c "\\[[0-9]*/$searchMonth/$searchYear:" "$file"

This regular expression searches for literal opening square bracket (backslashed to make it literal, because opening square bracket otherwise has a special meaning in regular expressions; doubled the backslash, because the backslash has special meaning to the shell in a double-qutoed string -- sorry if I'm going too fast :-) followed by any number, any number of times, followed by slash, followed by the search month, followed by slash, followed by the search year, followed by a colon.

egrep -c counts the number of matches, so you don't need the pipe to wc -l

You were already pretty close; merely combining the month and the year expression would already drastically reduce the number of false matches. Actually that's probably quite sufficient.

Code:
egrep -c /$searchMonth/$searchYear: "$file"

 

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regex(3)						     Library Functions Manual							  regex(3)

Name
       re_comp, re_exec - regular expression handler

Syntax
       char *re_comp(s)
       char *s;

       re_exec(s)
       char *s;

Description
       The  subroutine	compiles  a string into an internal form suitable for pattern matching.  The subroutine checks the argument string against
       the last string passed to

       The subroutine returns 0 if the string s was compiled successfully; otherwise a string containing an  error  message  is  returned.  If	is
       passed 0 or a null string, it returns without changing the currently compiled regular expression.

       The  subroutine returns 1 if the string s matches the last compiled regular expression, 0 if the string s failed to match the last compiled
       regular expression, and -1 if the compiled regular expression was invalid (indicating an internal error).

       The strings passed to both and may have trailing or embedded newline characters; they are terminated by	nulls.	 The  regular  expressions
       recognized are described in the manual entry for given the above difference.

Diagnostics
       The subroutine returns -1 for an internal error.

       The subroutine returns one of the following strings if an error occurs:

       No previous regular expression
       Regular expression too long
       unmatched (
       missing ]
       too many () pairs
       unmatched )

See Also
       ed(1), ex(1), egrep(1), fgrep(1), grep(1)

																	  regex(3)
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