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Full Discussion: removing frame charecters
Top Forums UNIX for Advanced & Expert Users removing frame charecters Post 302185591 by tkbharani on Tuesday 15th of April 2008 11:12:51 AM
Old 04-15-2008
RD=`date +%Y"-"%m"-"%d" "%T`
awk ' BEGIN{FS=OFS=","}
{
n=split($3,a1,"~")
split($4,a2,"~")
split($5,a3,"~")
for(i=1;i<=n;i++) {
print $1,$2,a1[i],a2[i],a3[i],$RD
}
}' file

I am writing this inside an shell script.In the above code if I add RD inside awk , its calling the value.How can I call the external value inside awk. i have bolded it.
 

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bytes(3pm)						 Perl Programmers Reference Guide						bytes(3pm)

NAME
bytes - Perl pragma to force byte semantics rather than character semantics SYNOPSIS
use bytes; no bytes; DESCRIPTION
The "use bytes" pragma disables character semantics for the rest of the lexical scope in which it appears. "no bytes" can be used to reverse the effect of "use bytes" within the current lexical scope. Perl normally assumes character semantics in the presence of character data (i.e. data that has come from a source that has been marked as being of a particular character encoding). When "use bytes" is in effect, the encoding is temporarily ignored, and each string is treated as a series of bytes. As an example, when Perl sees "$x = chr(400)", it encodes the character in UTF-8 and stores it in $x. Then it is marked as character data, so, for instance, "length $x" returns 1. However, in the scope of the "bytes" pragma, $x is treated as a series of bytes - the bytes that make up the UTF8 encoding - and "length $x" returns 2: $x = chr(400); print "Length is ", length $x, " "; # "Length is 1" printf "Contents are %vd ", $x; # "Contents are 400" { use bytes; print "Length is ", length $x, " "; # "Length is 2" printf "Contents are %vd ", $x; # "Contents are 198.144" } For more on the implications and differences between character semantics and byte semantics, see perlunicode. SEE ALSO
perlunicode, utf8 perl v5.8.0 2002-06-01 bytes(3pm)
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