using sed to replace a specific string on a specific line number using variables
this is where i am at
grep -v WARNING output | grep -v spawn | grep -v Passphrase | grep -v Authentication | grep -v '/sbin/tfadmin netguard -C'| grep -v 'NETWORK>' >> output.clean
grep -n Destination... (2 Replies)
Hi ,
I need some help on perl/sed conditional replacement
The situation is like below .
I have a file contents like below .
AAA|BBB|CCC|DDD
AAA|BCF|CCC|HHH
AAA|BVF|JJJ|KKK
Here in the above file . I know my second column value (taking "|" as my delimited )
Basically I have to... (3 Replies)
Given this row:
|lastname1|middlename1|firstname1|lastname2|middlename2|firstname2
produce this result:
|lastname|middlename|firstname
where the resultant names are based on the presence of the #2 names above. I.e., if a #2 name is passed (usually will be null,) use that - otherwise... (8 Replies)
Can someone tell me how I can do this?
e.g:
Say file1.txt contains:
today is monday
the 22 of
NOVEMBER
2010
and file2.txt contains:
the
11th
month
of
How do i replace the word NOVEMBER with (5 Replies)
hi experts,
i would like to do some html-file replacements and encounter the following problem: after cleaning up the file a bit i'd like to replace a regex with a reference and the content of another line. example:
/<title>\(*\) - Wikipedia<\/title>/
should be replaced by \1 (the title... (2 Replies)
I need to read the contents of a file. Then I need to grep for a keyword and replace part of the grepped line based on the condition of previous and present line.
Example input file:
V {
port1 = P;
port2 = 0;
shift_port = P0; /* if next shift_port is P0 I need... (9 Replies)
hi experts ,
I have an input like following.
R sfst 1000.0000
$ new time step for mass scaled calculation
R dt2ms -4.000E-7
$ friction value for blank
R mue ... (10 Replies)
Hi experts,
In my text file I have the following alot of lines like below.
input.k is as follows.
2684717 -194.7050476 64.2345581 150.6500092 0 0
2684718 -213.1575623 62.7032242 150.6500092 0 0
*INCLUDE
$# filename... (3 Replies)
here is what i want to achieve... consider a file contains below contents. the file size is large about 60mb
cat dump.sql
INSERT INTO `table1` (`id`, `action`, `date`, `descrip`, `lastModified`) VALUES (1,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10... (10 Replies)
How could be removed \n only if appearing at position 80 in the line? (4 Replies)
Discussion started by: RomanF
4 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)