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Full Discussion: LDAP authentication question
Special Forums UNIX and Linux Applications LDAP authentication question Post 302184360 by bptronics on Friday 11th of April 2008 08:45:54 AM
Old 04-11-2008
LDAP authentication question

Hello,
I have a Linux box with RHEL4 running on it. The box is meant to be on the DMZ. There is a directory on the box that will be remotely from time to time and I want a form of authentication on it.
Presently, I have configured Basic authentication with apache but the security is not tight.
I read about openldap and I need to know how I can use openldap with my box to authenticate remote users when about to view my box.
Can anyone please help me with this?
 

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Box(3I) 						    InterViews Reference Manual 						   Box(3I)

NAME
Box, HBox, VBox - tile interactors in a box SYNOPSIS
#include <InterViews/box.h> DESCRIPTION
A box is a scene of interactors that are tiled side-by-side in the available space. Interactors are placed left-to-right in a horizontal box, and top-to-bottom in a vertical box. A box will try to stretch or shrink the interactors inside it to fit the available space. The natural size of a box is the sum of its ele- ments along the major axis, and the maximum along its minor axis. A box's stretchability (shrinkability) is the sum of its elements along its major axis and the minimum of its elements along its minor axis. PUBLIC OPERATIONS
HBox(...) VBox(...) Create a new box. Zero to seven interactors may be passed as arguments; the interactors are inserted into the box. void Align(Alignment) Set the alignment mode that the box uses to place elements along the minor axis. The default alignment for an hbox is Bottom; other choices are Top and Center. The default alignment for a vbox is Left; other choices are Right and Center. void Insert(Interactor*) Append an interactor to the box. Components of an hbox (vbox) will appear left-to-right (top-to-bottom) in the order in which they are inserted. void Change(Interactor*) Notify the box that the given interactor's shape has changed. If change propagation is true, the box will modify its own shape to reflect the change and notify its parent. Regardless of propagation, the box will recompute the positions of the component interac- tors and update any that have changed. void Remove(Interactor*) Take an element of out a box. Remove does not cause any immediate change to the other components in the box; the Change operation must be called after one or more Removes to update the component positions. SEE ALSO
Glue(3I), Interactor(3I), Scene(3I), Shape(3I) InterViews 15 June 1987 Box(3I)
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