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Top Forums Shell Programming and Scripting sed remove everything up to the pattern Post 302183327 by ghostdog74 on Tuesday 8th of April 2008 09:35:29 PM
Old 04-08-2008
Quote:
Originally Posted by katrvu
I have been search all over the internet to find a solution to this.
I have a file that looks like:

-a ItemConfig.custom=true
-a Config.custom=true
go -t malu
-t Use=true

I want to get "malu" as output, and the werid thing is the blank before go is neither space nor tab.
what's the sed command to get the line contains "go -t" and remove everything up to -t????Smilie
Code:
awk '/go/{print $NF}' file

 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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