My program usage takes the form for example;
$ theApp 2 "one or more words"
i.e. 3 command line arguments; application name, an integer, some text
My code includes the following 4 lines:
int anInteger;
char words;
sscanf(argv, "%d", &anInteger);
sscanf(argv, "%s", &message);
Based... (2 Replies)
I have this while loop and at the end I am trying to get it to tell me the last argument I entered. And with it like this all I get is the sentence with no value for $1. Now I tried moving done after the sentence and it printed the value of $1 after every number. I don't want that I just want... (2 Replies)
Hi,
I have to store all the command line arguments into an array.
I have the following code.
**********************
#! /bin/sh
set -A arr_no_updates
i=1
while
do
arr_no_updates=$($i)
echo ${arr_no_updates}
i=$(($i+1))
done**************** (1 Reply)
I have this code, I thought it would automatically know the args sent to script when called from shell. But it seems to not see any...
main script:
. args
. errors
. opt
. clean
dbfile=""
opfile=""
# calls function in script below
chkarg
#check commands (2 Replies)
Hi I am executing a KSH script by passing command line arguments
example: Red Green Dark Red Blue
when I am splitting the arguments by using " "(Space) as delimiter
But the colour Dark Red is a single parameter. But it is getting splitted in between
How to avoid this. Please help Also... (4 Replies)
Hi,
i have a perl script named test.pl. It is executed as
cat *.log|test.pl
i need the complete command line args. I tried using basename $0 but im getting test.pl only but not cat *.log...
Can anyone help me on this.
Thanks in advance (3 Replies)
Hi,
Can you please hint me how to achieve the below?
Input:
$./script.sh start 1 2
Internally inside the script i want to set a single variable with $2 and $3 value?
Output:
CMD=$1
ARGS=$2 $3
--VInodh (10 Replies)
Hello All,
I have a Bash Script and an Expect script that together will SSH to another server and
do some stuff there... From within the Bash Script I process the Command Line Arguments,
which are Required Args and Optional Args.
When I call the Expect script from the Bash Script, I pass... (4 Replies)
I'm using getopts to process command line args in a Bash script. The code looks like this:
while getopts ":cfmvhs:t:" option; do
case $option in
c) operationMode="CHECK"
;;
f) operationMode="FAST"
;;
m) ... (6 Replies)
Discussion started by: gencon
6 Replies
LEARN ABOUT FREEBSD
getopt
GETOPT(1) BSD General Commands Manual GETOPT(1)NAME
getopt -- parse command options
SYNOPSIS
args=`getopt optstring $*` ; errcode=$?; set -- $args
DESCRIPTION
The getopt utility is used to break up options in command lines for easy parsing by shell procedures, and to check for legal options.
Optstring is a string of recognized option letters (see getopt(3)); if a letter is followed by a colon, the option is expected to have an
argument which may or may not be separated from it by white space. The special option '--' is used to delimit the end of the options. The
getopt utility will place '--' in the arguments at the end of the options, or recognize it if used explicitly. The shell arguments ($1 $2
...) are reset so that each option is preceded by a '-' and in its own shell argument; each option argument is also in its own shell argu-
ment.
EXIT STATUS
The getopt utility prints an error message on the standard error output and exits with status > 0 when it encounters an option letter not
included in optstring.
EXAMPLES
The following code fragment shows how one might process the arguments for a command that can take the options -a and -b, and the option -o,
which requires an argument.
args=`getopt abo: $*`
# you should not use `getopt abo: "$@"` since that would parse
# the arguments differently from what the set command below does.
if [ $? -ne 0 ]; then
echo 'Usage: ...'
exit 2
fi
set -- $args
# You cannot use the set command with a backquoted getopt directly,
# since the exit code from getopt would be shadowed by those of set,
# which is zero by definition.
while true; do
case "$1" in
-a|-b)
echo "flag $1 set"; sflags="${1#-}$sflags"
shift
;;
-o)
echo "oarg is '$2'"; oarg="$2"
shift; shift
;;
--)
shift; break
;;
esac
done
echo "single-char flags: '$sflags'"
echo "oarg is '$oarg'"
This code will accept any of the following as equivalent:
cmd -aoarg file file
cmd -a -o arg file file
cmd -oarg -a file file
cmd -a -oarg -- file file
SEE ALSO getopts(1), sh(1), getopt(3)HISTORY
Written by Henry Spencer, working from a Bell Labs manual page. Behavior believed identical to the Bell version. Example changed in FreeBSD
version 3.2 and 4.0.
BUGS
Whatever getopt(3) has.
Arguments containing white space or embedded shell metacharacters generally will not survive intact; this looks easy to fix but is not. Peo-
ple trying to fix getopt or the example in this manpage should check the history of this file in FreeBSD.
The error message for an invalid option is identified as coming from getopt rather than from the shell procedure containing the invocation of
getopt; this again is hard to fix.
The precise best way to use the set command to set the arguments without disrupting the value(s) of shell options varies from one shell ver-
sion to another.
Each shellscript has to carry complex code to parse arguments halfway correctly (like the example presented here). A better getopt-like tool
would move much of the complexity into the tool and keep the client shell scripts simpler.
BSD January 26, 2011 BSD