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Full Discussion: What does this error mean?
Top Forums Shell Programming and Scripting What does this error mean? Post 302182183 by Sueyoung88 on Saturday 5th of April 2008 11:18:42 PM
Old 04-06-2008
What does this error mean?

Hi all,

I am trying to come up a script to check the existence of a file, and I encountered the following error [: missing `]' when trying this script:

UNIX>. ck_file_name.ksh
[: missing `]'
file doesn't exist

#!/bin/ksh
export file_name=prod_fee_ctgry_1.log
if [ -f $file_name]; then
echo "file exists"
else
echo "file doesn't exist"
fi

This is the Sun Solaris.

Can anyone help?

Thanks!
 

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CUBRID_IS_INSTANCE(3)							 1						     CUBRID_IS_INSTANCE(3)

cubrid_is_instance - Check whether the instance pointed by OID exists

SYNOPSIS
int cubrid_is_instance (resource $conn_identifier, string $oid) DESCRIPTION
The cubrid_is_instance(3) function is used to check whether the instance pointed by the given $oid exists or not. PARAMETERS
o $conn_identifier -Connection identifier. o $oid -OID of the instance that you want to check the existence. RETURN VALUES
1, if such instance exists; 0, if such instance does not exist; -1, in case of error EXAMPLES
Example #1 cubrid_is_instance(3) example <?php $conn = cubrid_connect("localhost", 33000, "demodb"); $sql = <<<EOD SELECT host_year, medal, game_date FROM game WHERE athlete_code IN (SELECT code FROM athlete WHERE name='Thorpe Ian'); EOD; $req = cubrid_execute($conn, $sql, CUBRID_INCLUDE_OID); $oid = cubrid_current_oid($req); $res = cubrid_is_instance ($conn, $oid); if ($res == 1) { echo "Instance pointed by $oid exists. "; } else if ($res == 0){ echo "Instance pointed by $oid doesn't exist. "; } else { echo "error "; } cubrid_disconnect($conn); ?> The above example will output: Instance pointed by @0|0|0 doesn't exist. SEE ALSO
cubrid_drop(3), cubrid_get_class_name(3). PHP Documentation Group CUBRID_IS_INSTANCE(3)
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