Hi all,
I have a variable say var1 (output from somewhere, which I can't change)which store something like this:
echo $var1
name=fred
age=25
address="123 abc"
password=pass1234
how can I make the variable $name, $age, $address and $password contain the info?
I mean do this in a... (1 Reply)
Hallo!
Example.
#!/bin/bash
BACKUP_DIR=/home/userx/backups/evolution
echo $BACKUP_DIR
# delete the first character from the string
BACKUP_DIR=$(echo $BACKUP_DIR | cut -c 2-)
echo $BACKUP_DIR
It works. It does want I want, delete the first character from string in the... (11 Replies)
Hi ,
I want to read below output, lets called it output1.txt and each string for every line will be declare as a variables.
This is the input file
196 server_a server_unix_2 FW
196 server_b server_win_1 CD
196 server_c server_win_2 CD
196 server_bd ... (2 Replies)
can anyone please help me with this:
i have written a shell script and a stored procedure which has one OUT parameter. now i want to use that out parameter as an input to the unix script but i am getting an error as variable not found. below are the unix scripts and stored procedure...
... (4 Replies)
I have two variables,
my $filename = "abc_yyyy_mm_dd.txt";
my $filename1 = " abc_2011_11_07.txt";
I need to perform some operations after checking if $filename has $filename1 in it
i have used the below code,
if($filename =~ /^$filename1/)
{
----
--
} (2 Replies)
I need to remove double quoted strings from specific lines in a file. The specific line numbers are a variable. For example, line 5 of the file contains
A B C "string"
I want to remove "string". The following sed command works:
sed '5 s/\"*\"//' $file
If there are multiple... (2 Replies)
Greetings Experts,
As part of automating the sql generation, I have the source table name, target table name, join condition stored in a file join_conditions.txt which is a delimited file (I can edit the file if for any reason). The reason I needed to store is I have built SELECT list without... (5 Replies)
Hi
I have the follwoing requirement
I have a file as follows:
# cat priy
yyy.poweroff_cmd = /sbin/poweroff
hhh.powersave-nap = 1
When this file is provided as input, I first used "awk" command and saved variables present after "="
replace=$line
replace1=`echo $line | awk -F "="... (3 Replies)
The bash bash below extracts the oldest folder from a directory and stores it in filename
That result will match a line in bold in input. In the matching line there is an_xxx digit in italics that
(once the leading zero is removed) will match a line in link. That is the lint to print in output.... (2 Replies)
For example: I am grepping "Hello" from a file and there are 10 matches. So all ten lines with match will get stored into a variable($match). Now I want to ignore those lines which have "Hi" present in that.
Currently I tried this: match = grep "Hello" file | grep -v "Hi" file
But that's not... (2 Replies)
Discussion started by: pavan
2 Replies
LEARN ABOUT REDHAT
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep is used to invoke the grep on compress'ed or gzip'ed files. All options specified are passed directly to grep. If no file is speci-
fied, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and
fed to grep.
If zgrep is invoked as zegrep or zfgrep then egrep or fgrep is used instead of grep. If the GREP environment variable is set, zgrep uses
it as the grep program to be invoked. For example:
for sh: GREP=fgrep zgrep string files
for csh: (setenv GREP fgrep; zgrep string files)
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), egrep(1), fgrep(1), zdiff(1), zmore(1), znew(1), zforce(1), gzip(1), gzexe(1)ZGREP(1)