Sponsored Content
Top Forums Shell Programming and Scripting Getting error in command line arguments Post 302181498 by sunitachoudhury on Thursday 3rd of April 2008 06:29:23 AM
Old 04-03-2008
Hi ag79,

ya i also don't want to put my password.

Is there any way to hide the password. Actually i want to do the validation of my id and password before logining into FTP

Can anybody help me??????
 

10 More Discussions You Might Find Interesting

1. Programming

command line arguments

Hi How to pass multi line text as a command line argument to a program. (i.e) ./a.out hi this is sample 0 file1 where hi this is sample should be stored in argv 0 in argv and so on... (3 Replies)
Discussion started by: bankpro
3 Replies

2. UNIX for Dummies Questions & Answers

arguments in command line

Hi all, How many arguments can we pass while testing a prgm at command line.. I encountered an issue while passing 10 arguments. For $10 its taking argument passed for $1 followed by 'zero'. can we pass more than 9 arguments /Is there any other way. Thanks, rrs (6 Replies)
Discussion started by: rrs
6 Replies

3. Shell Programming and Scripting

command line arguments

-------------------------------------------------------------------------------- I have this while loop and at the end I am trying to get it to tell me the last argument I entered. And with it like this all I get is the sentence with no value for $1. Now I tried moving done after the sentence... (1 Reply)
Discussion started by: skooly5
1 Replies

4. UNIX for Dummies Questions & Answers

Command line arguments.

I am working on a script wherein i need the user to enter the Build ID for eg:the command line will show enter the build ID Now on entering the build ID it should be assigned to @ARGV. How can this be done.? (1 Reply)
Discussion started by: Varghese
1 Replies

5. Shell Programming and Scripting

Maximum command line arguments

Hi, Can anyone please help me to know what is the maximum number of command line arguments that we can pass in unix shell script? Thanks in advance, Punitha.S (2 Replies)
Discussion started by: puni
2 Replies

6. UNIX for Dummies Questions & Answers

command line arguments

hi, can someone how to accept command line arguments as a variable using in script? like: ./scriptname arguments by accept arguments, I can use it in my script? thx! (1 Reply)
Discussion started by: ikeQ
1 Replies

7. Shell Programming and Scripting

Command Line Arguments - not working

I am new to the world of Unix and shell scripting and have been trying to get the following simple script to work: #!/bin/bash echo "what is your age?" echo "you are $1 years old"I want to be able to enter my age on the command line, when prompted, and it return the... (1 Reply)
Discussion started by: meursault
1 Replies

8. Shell Programming and Scripting

command line arguments

hi,,,, I want to create a command prompt, for example "prompt>", so my prompt need to handle commands, for example "prompt>cmd", so i want to know how to get arguments for my own commands cmd, i.e. default argc should contain arguments count and argv should point to the argument vector i.e, for... (2 Replies)
Discussion started by: vins_89
2 Replies

9. Shell Programming and Scripting

Command line arguments for addition

Hi all, I am trying to write a code for addition of n numbers which will be passed by the user as command line arguments. I wrote the following code. add=0 for (( i = 1 ; i <= $# ; i++ )) do add=`expr $i + $add` done #echo "sum is : $add" input : $./add.sh 12 32 14... (7 Replies)
Discussion started by: PranavEcstasy
7 Replies

10. UNIX for Beginners Questions & Answers

Loop with command line arguments

Ubuntum, Bash version: 4.3.46 Hi, how can I create a loop where the command line arguments change (increase) and every time the number of arguments is different ? ### I have many gene names... that mean gene1=$2, gene2=$3, ...... geneN=$N+1 ### some time the number of gene is 25, other... (7 Replies)
Discussion started by: echo manolis
7 Replies
lpasswd(8)						      System Manager's Manual							lpasswd(8)

NAME
lpasswd - Change group or user password SYNOPSIS
lpasswd [OPTION]... [name] DESCRIPTION
Changes password of user or group name. If the name argument is not provided, username of the invoking user is used; the name argument is ignored if lpasswd is run set-uid to a different user. Entering an empty password (by pressing Enter) aborts the password setting operation. OPTIONS
-F, --plainpassword-fd=fd Read password from file descriptor fd, terminated by end of file, ' ' or ' '. -f, --password-fd=fd Read password hash from file descriptor fd, terminated by end of file, ' ' or ' '. -g, --group Change password of group name. By default the password of user name is changed. -i, --interactive Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration. -P, --plainpassword=password Set the password to password. Note that the password can be viewed while running lpasswd using tools such as ps(1). -p, --password=encrypted Set the password to the password represented by the hash encrypted. Note that the hash can be viewed while running lpasswd using tools such as ps(1). EXIT STATUS
The exit status is 0 on success, nonzero on error. libuser Jan 12 2005 lpasswd(8)
All times are GMT -4. The time now is 07:18 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy