Hi guys,
I have no idea on unix but suddenly, my cobol programs calls a unix script that i know nothing about.
can you guys interpret these lines for me?
i know its a print command but I want to actually know how many copies it prints.
qprt -da -P $1 -t '6' -i '6' -l '70' $2
qprt -da... (1 Reply)
HI All,
Im encountering behaviour that is not correct for my requirements when I untar a file.
Im using the below command to tar up files from various folders to the ARCHIVE folder as below...
tar -cvf "$ARCHIVE_PATH"/"$dte_tar_filename" "$LOG_PATH" "$PROCESSED_PATH2" "$ERROR_PATH"
... (5 Replies)
Was wondering if someone could interpret this for me -- I'm not sure what everything means. It's a shell script from my bash book:
cd ()
{
builtin cd "$@"
es=$?
echo "$OLDPWD ->$PWD"
return $es
}
what I don't quite understand is the "$@". I think, if I understand... (6 Replies)
Hi,
I have a function in a bash script that returns a string after some operations using awk.
The following code returns 555
$VARIABLE="EXAMPLE"
get_number $VARIABLE
this value I'd like to pass it as a second argument of another script with the following usage
myscript.sh <param1>... (7 Replies)
Ksh is my default shell, but I want use the bash shell since its convenient to me.
When I type a long command line in a terminal, it does not wrap to the next line when I reach the end of the line and it wraps onto the same line, overwriting my prompt and the rest of what I typed.
$... (5 Replies)
I had been looking at page 75 of this online book:
http://richard.esplins.org/static/downloads/linux_book.pdf
I've used the system function in C to call bash commands before, but wanted to learn this way too. The solution in the book worked perfectly. However, I tried changing the simple "ls -l... (3 Replies)
I booted into single user mode with
/usr/sbin/reboot -- -s
but after doing a control -d
my
who -r
shows
run-level 3 Nov 17 14:07 3 0 S
I was expecting it to show run-level S
why is this still in run level 3?
thanks (1 Reply)
Hi,
I am new in bash scripting. In my work, I provide support to several users and when I connect to their computers I use the same admin and password, so I am trying to create a script that will only ask me for the IP address and then connect to the computer without having me to type the user... (5 Replies)
Discussion started by: arcoa05
5 Replies
LEARN ABOUT SUSE
eval
eval(n) Tcl Built-In Commands eval(n)
__________________________________________________________________________________________________________________________________________________NAME
eval - Evaluate a Tcl script
SYNOPSIS
eval arg ?arg ...?
_________________________________________________________________DESCRIPTION
Eval takes one or more arguments, which together comprise a Tcl script containing one or more commands. Eval concatenates all its argu-
ments in the same fashion as the concat command, passes the concatenated string to the Tcl interpreter recursively, and returns the result
of that evaluation (or any error generated by it). Note that the list command quotes sequences of words in such a way that they are not
further expanded by the eval command.
EXAMPLES
Often, it is useful to store a fragment of a script in a variable and execute it later on with extra values appended. This technique is
used in a number of places throughout the Tcl core (e.g. in fcopy, lsort and trace command callbacks). This example shows how to do this
using core Tcl commands:
set script {
puts "logging now"
lappend $myCurrentLogVar
}
set myCurrentLogVar log1
# Set up a switch of logging variable part way through!
after 20000 set myCurrentLogVar log2
for {set i 0} {$i<10} {incr i} {
# Introduce a random delay
after [expr {int(5000 * rand())}]
update ;# Check for the asynch log switch
eval $script $i [clock clicks]
}
Note that in the most common case (where the script fragment is actually just a list of words forming a command prefix), it is better to |
use {*}$script when doing this sort of invocation pattern. It is less general than the eval command, and hence easier to make robust in |
practice. The following procedure acts in a way that is analogous to the lappend command, except it inserts the argument values at the
start of the list in the variable:
proc lprepend {varName args} {
upvar 1 $varName var
# Ensure that the variable exists and contains a list
lappend var
# Now we insert all the arguments in one go
set var [eval [list linsert $var 0] $args]
}
However, the last line would now normally be written without eval, like this: |
set var [linsert $var 0 {*}$args] |
SEE ALSO
catch(n), concat(n), error(n), interp(n), list(n), namespace(n), subst(n), tclvars(n), uplevel(n)
KEYWORDS
concatenate, evaluate, script
Tcl eval(n)