I checked the code but it is not working
cat > file6
E106,0,1/9/1993,0,E001,E003,A,45200,3766.667,21.730769
$ cat file6 | sed -e 's/([0-9][0-9])-([[:alpha:]]+)-([0-9]{4})/$3$2$1/'
E106,0,1/9/1993,0,E001,E003,A,45200,3766.667,21.730769
it is giving the same formate.......And i need to validate every line
in a file
Hello,
I want to convert MM DD YYYY date format to MM-DD-YYYY format.
For exemple:
I have to convert Nov 28 2005 to 28-11-2005.
Thenks for youf help.
DAFI (2 Replies)
Hi
I want to convert MAY 05 2005 01:15:00PM date format to 2005/05/05 01:15:00PM .
CAn somebody suggest me a code ,I am new to unix shell programming.
Thanks
Arif (21 Replies)
Hi,
I have the string YYYYMMDDHHMMSS like 20090801204150 and I need to convert it using the unix command date in the format:
date "Saturday, 1 August 2009 20:40:59"
All in one single Unix line if this is possible. What's the correct syntax?
Steve Hagi (6 Replies)
Hi all,
I require to convert julian date to normal calander date in unix
for eg julian date=122
now i want corresponding calander date
----------------------------------------
gr8 if give very small command/script
and please explain the steps as well(imp)
Thanks
... (3 Replies)
Trying to convert dates using a Perl Script but it has to accept formats like
3 letter month, day and year like Nov 02 2010 or 1/4/11 or 21 Feb 2011 and have it convert to something like October 20, 2011. Any ideas? (2 Replies)
Hi ,
we have a string with yyyymmdd format .
how to know which date it is ?
example:20120712-->sunday
20150228-->saturday
20140431-->invalid
please suggest commands which work on below
os : SunOS 5.10
shell: bash shell
Thanks,
Srinath. (10 Replies)
Discussion started by: srinadhreddy27
10 Replies
LEARN ABOUT LINUX
unbuffer
UNBUFFER(1) General Commands Manual UNBUFFER(1)NAME
unbuffer - unbuffer output
SYNOPSIS
unbuffer program [ args ]
INTRODUCTION
unbuffer disables the output buffering that occurs when program output is redirected from non-interactive programs. For example, suppose
you are watching the output from a fifo by running it through od and then more.
od -c /tmp/fifo | more
You will not see anything until a full page of output has been produced.
You can disable this automatic buffering as follows:
unbuffer od -c /tmp/fifo | more
Normally, unbuffer does not read from stdin. This simplifies use of unbuffer in some situations. To use unbuffer in a pipeline, use the
-p flag. Example:
process1 | unbuffer -p process2 | process3
CAVEATS
unbuffer -p may appear to work incorrectly if a process feeding input to unbuffer exits. Consider:
process1 | unbuffer -p process2 | process3
If process1 exits, process2 may not yet have finished. It is impossible for unbuffer to know long to wait for process2 and process2 may
not ever finish, for example, if it is a filter. For expediency, unbuffer simply exits when it encounters an EOF from either its input or
process2.
In order to have a version of unbuffer that worked in all situations, an oracle would be necessary. If you want an application-specific
solution, workarounds or hand-coded Expect may be more suitable. For example, the following example shows how to allow grep to finish pro-
cessing when the cat before it finishes first. Using cat to feed grep would never require unbuffer in real life. It is merely a place-
holder for some imaginary process that may or may not finish. Similarly, the final cat at the end of the pipeline is also a placeholder
for another process.
$ cat /tmp/abcdef.log | grep abc | cat
abcdef
xxxabc defxxx
$ cat /tmp/abcdef.log | unbuffer grep abc | cat
$ (cat /tmp/abcdef.log ; sleep 1) | unbuffer grep abc | cat
abcdef
xxxabc defxxx
$
BUGS
The man page is longer than the program.
SEE ALSO
"Exploring Expect: A Tcl-Based Toolkit for Automating Interactive Programs" by Don Libes, O'Reilly and Associates, January 1995.
AUTHOR
Don Libes, National Institute of Standards and Technology
1 June 1994 UNBUFFER(1)