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Full Discussion: I can't seem to pass variables properly into a nawk statement
Top Forums Shell Programming and Scripting I can't seem to pass variables properly into a nawk statement Post 302180251 by DeCoTwc on Sunday 30th of March 2008 02:04:14 PM
Old 03-30-2008
Quote:
Originally Posted by rubin
Hi,

Given that AWK has a special way of passing variables into it, "$m" and "$d" are not recognized within AWK, it knows only m ( m="$m" ) and d ( d="$d" ).

Code:
nawk -v m=$m -v d=$d  '{if ($1 == "$m" && $2 == "$d") print "success"}'     # incorrect use of passing variables

So the correct use is:
Code:
nawk -v m=$m -v d=$d  '{if ($1 == m && $2 == d) print "success"}'

That was it. I KNEW it was going to come down to me not understanding the syntax correctly. Thank you so much for your succinct answer.

era, you got there first, and rubin, you made it all clear. Again, thank you.

and once I uncommented (and remembered to add ;then) to my if statement, I got the log dump I was looking for.

Just out of curiosity, did I choose a completely convoluted solution to my issue (dumping only todays log) or was this at least remotely a intelligent method?
 

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