03-28-2008
Then modify the sed script to only print when that particular key is matched.
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1. Shell Programming and Scripting
What is the more efficient way to do this (awk only and default FS) ?
$ echo "jefe@alm"|awk '{pos = index($0, "@");printf ("USER: %s\n",substr ($0,1,pos-1))}'
USER: jefe
Thx in advance (2 Replies)
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2. UNIX for Dummies Questions & Answers
Hi,
My input file is
41;2;xxxx;yyyyy....
41;2;xxxx;yyyyy....
41;2;xxxx;yyyyy....
..
..
I need to change the second field value from 2 to 1. i.e.,
41;1;xxxx;yyyyy....
41;1;xxxx;yyyyy....
41;1;xxxx;yyyyy....
..
..
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3. Shell Programming and Scripting
Hi I am trying to run this command in ksh ...its not working
$line="123356572867116w1671716"
actual_length = 16
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the substr is not giving me an output
how can i make it done
can anyone hwlp me on this
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Hi, i'm a newbie and i don't know unix...
I'm a dba oracle.
I need to cat the content of a file like this:
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can anybody explain this code?
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Hello life savers!!
Is there any way to use substr in awk command for returning one part of a string from declared start and stop point?
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substr(string, start, length)
Do we have anything like possible to use in awk ? :
substr(string, start, stop)
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8. Shell Programming and Scripting
I have a command like this:
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This syntax doesn't work. But I was able to get this to work:
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Hi,
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awk '/^>/{id=$0;next}length>=7 { print id, "\n"$0}' Test.txt
Can I use substr to achieve the same task?
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