03-28-2008
Then modify the sed script to only print when that particular key is matched.
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1. Shell Programming and Scripting
What is the more efficient way to do this (awk only and default FS) ?
$ echo "jefe@alm"|awk '{pos = index($0, "@");printf ("USER: %s\n",substr ($0,1,pos-1))}'
USER: jefe
Thx in advance (2 Replies)
Discussion started by: Klashxx
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2. UNIX for Dummies Questions & Answers
Hi,
My input file is
41;2;xxxx;yyyyy....
41;2;xxxx;yyyyy....
41;2;xxxx;yyyyy....
..
..
I need to change the second field value from 2 to 1. i.e.,
41;1;xxxx;yyyyy....
41;1;xxxx;yyyyy....
41;1;xxxx;yyyyy....
..
..
Thanks in advance. (9 Replies)
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3. Shell Programming and Scripting
Hi I am trying to run this command in ksh ...its not working
$line="123356572867116w1671716"
actual_length = 16
cut_line=`awk 'BEGIN{print substr(ARGV,1,actual_length)}' "$line"`
the substr is not giving me an output
how can i make it done
can anyone hwlp me on this
cut_line=`awk... (2 Replies)
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Hi, i'm a newbie and i don't know unix...
I'm a dba oracle.
I need to cat the content of a file like this:
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oracle 405626 1 0 Sep 17 - 8:39 ora_pmon_ORCL1
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can anybody explain this code?
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Hello life savers!!
Is there any way to use substr in awk command for returning one part of a string from declared start and stop point?
I mean I know we have this:
substr(string, start, length)
Do we have anything like possible to use in awk ? :
substr(string, start, stop)
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I have a command like this:
listdb ID923 -l |gawk '{if (substr($0,37,1)==1 && NR == 3)print "YES" else if (substr ($0,37,1)==0 && NR == 3) print "NO"}'
This syntax doesn't work. But I was able to get this to work:
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Hi,
- In a file test.wmi
Col1 | firstName | lastName
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awk '/^>/{id=$0;next}length>=7 { print id, "\n"$0}' Test.txt
Can I use substr to achieve the same task?
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LEARN ABOUT LINUX
shtool-subst
SHTOOL-SUBST.TMP(1) GNU Portable Shell Tool SHTOOL-SUBST.TMP(1)
NAME
shtool-subst - GNU shtool sed(1) substitution operations
SYNOPSIS
shtool subst [-v|--verbose] [-t|--trace] [-n|--nop] [-w|--warning] [-q|--quiet] [-s|--stealth] [-i|--interactive] [-b|--backup ext]
[-e|--exec cmd] [-f|--file cmd-file] [file] [file ...]
DESCRIPTION
This command applies one or more sed(1) substitution operations to stdin or any number of files.
OPTIONS
The following command line options are available.
-v, --verbose
Display some processing information.
-t, --trace
Enable the output of the essential shell commands which are executed.
-n, --nop
No operation mode. Actual execution of the essential shell commands which would be executed is suppressed.
-w, --warning
Show warning on substitution operation resulting in no content change on every file. The default is to show a warning on substitution
operations resulted in no content change on all files.
-q, --quiet
Suppress warning on substitution operation resulting in no content change.
-s, --stealth
Stealth operation. Preserve timestamp on file.
-i, --interactive
Enter interactive mode where the user has to approve each operation.
-b, --backup ext
Preserve backup of original file using file name extension ext. Default is to overwrite the original file.
-e, --exec cmd
Specify sed(1) command directly.
-f, --file cmd-file
Read sed(1) command from file.
EXAMPLE
# shell script
shtool subst -i -e 's;(c) ([0-9]*)-2000;(c) 1-2001;' *.[ch]
# RPM spec-file
%install
shtool subst -v -n
-e 's;^(prefix=).*;1 $RPM_BUILD_ROOT%{_prefix};g'
-e 's;^(sysconfdir=).*;1 $RPM_BUILD_ROOT%{_prefix}/etc;g'
`find . -name Makefile -print`
make install
HISTORY
The GNU shtool subst command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 2001 for GNU shtool. It was prompted
by the need to have a uniform and convenient patching frontend to sed(1) operations in the OpenPKG package specifications.
SEE ALSO
shtool(1), sed(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-SUBST.TMP(1)