What is the more efficient way to do this (awk only and default FS) ?
$ echo "jefe@alm"|awk '{pos = index($0, "@");printf ("USER: %s\n",substr ($0,1,pos-1))}'
USER: jefe
Thx in advance (2 Replies)
Hi,
My input file is
41;2;xxxx;yyyyy....
41;2;xxxx;yyyyy....
41;2;xxxx;yyyyy....
..
..
I need to change the second field value from 2 to 1. i.e.,
41;1;xxxx;yyyyy....
41;1;xxxx;yyyyy....
41;1;xxxx;yyyyy....
..
..
Thanks in advance. (9 Replies)
Hi I am trying to run this command in ksh ...its not working
$line="123356572867116w1671716"
actual_length = 16
cut_line=`awk 'BEGIN{print substr(ARGV,1,actual_length)}' "$line"`
the substr is not giving me an output
how can i make it done
can anyone hwlp me on this
cut_line=`awk... (2 Replies)
Hi, i'm a newbie and i don't know unix...
I'm a dba oracle.
I need to cat the content of a file like this:
> ps -eaf|grep pmon
oracle 221422 1 0 Sep 17 - 7:20 ora_pmon_ORCL
oracle 405626 1 0 Sep 17 - 8:39 ora_pmon_ORCL1
oracle 491534 1 0 ... (3 Replies)
Hello life savers!!
Is there any way to use substr in awk command for returning one part of a string from declared start and stop point?
I mean I know we have this:
substr(string, start, length)
Do we have anything like possible to use in awk ? :
substr(string, start, stop)
... (9 Replies)
I have a command like this:
listdb ID923 -l |gawk '{if (substr($0,37,1)==1 && NR == 3)print "YES" else if (substr ($0,37,1)==0 && NR == 3) print "NO"}'
This syntax doesn't work. But I was able to get this to work:
listdb ID923 -l |gawk '{if (substr($0,37,1)==1 && NR == 3)print "YES"}'
... (4 Replies)
Hi,
- In a file test.wmi
Col1 | firstName | lastName
4003 | toto_titi_CT- | otot_itit
- I want to have only ( colones $7,$13 and $15) with code 4003 and 4002. for colone $13 I want to have the whole name untill _CT- or _GC-
1- I used the command egrep with awk
#egrep -i... (2 Replies)
awk '/^>/{id=$0;next}length>=7 { print id, "\n"$0}' Test.txt
Can I use substr to achieve the same task?
Thanks! (8 Replies)
Discussion started by: Xterra
8 Replies
LEARN ABOUT MOJAVE
systemd-ask-password-wall.service
SYSTEMD-ASK-PASSWORD-CONSOLE.SERVICE(8) systemd-ask-password-console.service SYSTEMD-ASK-PASSWORD-CONSOLE.SERVICE(8)NAME
systemd-ask-password-console.service, systemd-ask-password-console.path, systemd-ask-password-wall.service, systemd-ask-password-wall.path
- Query the user for system passwords on the console and via wall
SYNOPSIS
systemd-ask-password-console.service
systemd-ask-password-console.path
systemd-ask-password-wall.service
systemd-ask-password-wall.path
DESCRIPTION
systemd-ask-password-console.service is a system service that queries the user for system passwords (such as hard disk encryption keys and
SSL certificate passphrases) on the console. It is intended to be used during boot to ensure proper handling of passwords necessary for
boot. systemd-ask-password-wall.service is a system service that informs all logged in users for system passwords via wall(1). It is
intended to be used after boot to ensure that users are properly notified.
See the developer documentation[1] for more information about the system password logic.
Note that these services invoke systemd-tty-ask-password-agent(1) with either the --watch --console or --watch --wall command line
parameters.
SEE ALSO systemd(1), systemd-tty-ask-password-agent(1), wall(1)NOTES
1. developer documentation
https://www.freedesktop.org/wiki/Software/systemd/PasswordAgents
systemd 237SYSTEMD-ASK-PASSWORD-CONSOLE.SERVICE(8)