03-18-2008
find command takes a lot of time ( can I skip directories)
I have a file called "library" with the following content
libnxrdbmgr.a
libnxrdbmgr.so
libnxtk.a
libnxtk.so
libora0d_nsc_osi.so
I am trying to locate if these libraries are on my machine or not. find command runs for about few seconds and hangs after this.
Can someone please help me and let me know if there is a better way. Is there a way I can ignore a directory and its sub directories during the find process
find: cannot read dir /ssttools/performance/RMCmem: Permission denied
$ for i in `cat library`
do
find / -name $i -print | grep $i >> outputfile
done
find: cannot read dir /proc/24250: Permission denied
find: cannot read dir /proc/17502: Permission denied
find: cannot read dir /tmp/smc898: Permission denied
find: cannot read dir /tmp/config_pvr: Permission denied
find: cannot read dir /export/home/dwgore/.rhosts: Permission denied
find: cannot read dir /export/home/mgalvin/.rhosts: Permission denied
find: cannot read dir /export/home/nmsbb/.ssh: Permission denied
find: cannot read dir /export/home/www/.ssh: Permission denied
find: cannot read dir /ssttools/performance/RMCmem: Permission denied
It is taking a lot of time here before it can go to next
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LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)