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Top Forums Shell Programming and Scripting A simple find and replace without using any regex (bash) Post 302176380 by era on Tuesday 18th of March 2008 08:08:29 AM
Old 03-18-2008
Oh, and if you are really strict about bash, try this:

Code:
read input
while read line; do
  case $line in
    $input) echo ;;  # or not, if you want the newline gone, too
    *) echo "$line";;
  esac
done <file

era
 

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IN_ARRAY(3)								 1							       IN_ARRAY(3)

in_array - Checks if a value exists in an array

SYNOPSIS
bool in_array FALSE (mixed $needle, array $haystack, [bool $strict]) DESCRIPTION
Searches $haystack for $needle using loose comparison unless $strict is set. PARAMETERS
o $needle - The searched value. Note If $needle is a string, the comparison is done in a case-sensitive manner. o $haystack - The array. o $strict - If the third parameter $strict is set to TRUE then the in_array(3) function will also check the types of the $needle in the $haystack. RETURN VALUES
Returns TRUE if $needle is found in the array, FALSE otherwise. EXAMPLES
Example #1 in_array(3) example <?php $os = array("Mac", "NT", "Irix", "Linux"); if (in_array("Irix", $os)) { echo "Got Irix"; } if (in_array("mac", $os)) { echo "Got mac"; } ?> The second condition fails because in_array(3) is case-sensitive, so the program above will display: Got Irix Example #2 in_array(3) with strict example <?php $a = array('1.10', 12.4, 1.13); if (in_array('12.4', $a, true)) { echo "'12.4' found with strict check "; } if (in_array(1.13, $a, true)) { echo "1.13 found with strict check "; } ?> The above example will output: 1.13 found with strict check Example #3 in_array(3) with an array as needle <?php $a = array(array('p', 'h'), array('p', 'r'), 'o'); if (in_array(array('p', 'h'), $a)) { echo "'ph' was found "; } if (in_array(array('f', 'i'), $a)) { echo "'fi' was found "; } if (in_array('o', $a)) { echo "'o' was found "; } ?> The above example will output: 'o' was found SEE ALSO
array_search(3), isset(3), array_key_exists(3). PHP Documentation Group IN_ARRAY(3)
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