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Full Discussion: Problem with double quote and string variable
Top Forums Shell Programming and Scripting Problem with double quote and string variable Post 302176203 by mattemp on Monday 17th of March 2008 06:00:36 PM
Old 03-17-2008
Quote:
Originally Posted by KevinADC
open the file and remove the quotes if you have no control over the file format. Then split the fields on the spaces to create a list of files to feed to the zip function.

Post your current code (or just the relevant part) for more help.
Here is the part of my script where I need my files list:
Code:
LIST=$(tail -1 $FILE)
cvs log -N -r$rev1:$rev2 $LIST > changelog.txt

My file looks like this :
Code:
"java/file1.java" "java/file2.java" "java/file3.java" "java/file4.java" "java/file5.java"

It is the output of a xslt processing so I do have control on it. I can generate a file which looks like this, without quotes and my script works perfectly :
Code:
java/file1.java java/file2.java java/file3.java java/file4.java java/file5.java

But I wanted to wrap the filenames around quotes in case some of the filenames contain whitespaces.

So maybe I should just work on my xsl stylesheet in order to escape whitespaces in filenames?
 

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								    07 Aug 2006 						      schemagen(1)
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