Hi...I need some help with a date script. I need to allow the user to enter the month (alpha) day (int) and year (YYYY) and count the difference in number of days since Jan 1, 1952 to the users date. I've been messing with this for about 10 hours and I think I'm just making the script worse =(
... (1 Reply)
Hi
Can any buddy give mi a simple program or logic or command which will get
difference between two dates
ex:diff between 20051008 2005908 is 24hours 12 min 2 sec
regards (1 Reply)
if there are two date one is entered by user
and another is system date than how can we finds day difference
between these two date
try to make it within 4 lines (2 Replies)
Hi All!
I would like to know the time difference between two dates which are in same format...
$ date -r abc
Thu Oct 29 09:40:37 EDT 2009
$ date
Fri Oct 30 02:07:03 EDT 2009
i would like to find the diff between these two dates in hours..please help..:)
Regards,
Kiran (3 Replies)
Dear all,
I fancy that I'm pretty competent in ksh, but I have someone on HP-UX wanting me to script up a simple interface to handle user alterations rather than giving them high privileges to run up SAM. This is all fairly straightforward, but I'm stuck on an epoch date issue.
When we have... (6 Replies)
1. The problem statement, all variables and given/known data:
The problem i have is that i probably make a few mistake here in the code but don't know what it is and i try to get the date difference but don't know where to add the days_in_month function
2. Relevant commands, code,... (1 Reply)
I tried the below code to find difference between two dates. It works fine if the day of the month is 2-digit number. But it fails when we have a single-digit day of month(ex:1-9). my code is as below. please help me soon.
#!/usr/bin/perl -w
use strict;
use Time::Local;
... (2 Replies)
Hi Everyone,
We are having an issue with date and date -u in our AIX Systems.
We have checked environment variable TZ and /etc/environment and however, we could not rectify the difference.
>date
Thu Mar 19 22:31:40 IST 2015
>date -u
Thu Mar 19 17:01:44 GMT 2015
Any clue... (5 Replies)
Hi,
I created a script for finding the duration of a job using the start and end time of the job. But the command doesnt calculate correct value if the duration is more than 24 hours. Any help would be really good
.
cat test1 --- start time
03/27/15 17:41:00
03/24/15 11:58:04
03/23/15... (3 Replies)
Discussion started by: rogerben
3 Replies
LEARN ABOUT PHP
px_timestamp2string
PX_TIMESTAMP2STRING(3)PX_TIMESTAMP2STRING(3)px_timestamp2string - Converts the timestamp into a string.SYNOPSIS
string px_timestamp2string (resource $pxdoc, float $value, string $format)
DESCRIPTION
Turns a timestamp as it stored in the paradox file into human readable format. Paradox timestamps are the number of miliseconds since
0001-01-02. This function is just for convenience. It can be easily replaced by some math and the calendar functions as demonstrated in the
following example.
PARAMETERS
o $pxdoc
- Resource identifier of the paradox database.
o $value
- Value as stored in paradox database field of type PX_FIELD_TIME, or PX_FIELD_TIMESTAMP.
o $format
- String format similar to the format used by date(3). The placeholders support by this function is a subset of those supported by
date(3) (Y, y, m, n, d, j, H, h, G, g, i, s, A, a, L).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
Turn a paradox timestamp into a human readable form
<?php
$px = px_new();
/* make up a date as it could be stored in */
/* a date field of a paradox db. */
/* 700000 days since 1.1.0000. */
$days = 700000;
/* Use the calendar functions to print a */
/* human readable format of the date */
echo jdtogregorian($days+1721425)."
";
/* Turn it into a timestamp as it stored in a paradox database */
/* Timestamps are stored in miliseconds since 0001-01-02 */
$stamp = $days * 86400.0 * 1000.0;
/* Add one hour */
$stamp += 3600000.0;
/* The following will output '7/15/1917 01:00:00'. */
echo px_timestamp2string($px, $stamp, "n/d/Y H:i:s")."
";
px_delete($px);
?>
The above example will output:
7/15/1917
7/15/1917 01:00:00
The Julian day count as passed to jdtogregorian(3) has a different base of 1.1.4714 b.c. and must therefore be calculated by adding
1721425 to the day count used in the paradox file. Turning the day count into a timestamp is easily done by multiplying with 86400000.0 to
obtain miliseconds.
SEE ALSO px_date2string(3), jdtogregorian(3).
PHP Documentation Group PX_TIMESTAMP2STRING(3)