Sponsored Content
Top Forums Shell Programming and Scripting Days difference between two dates Post 302174562 by jaduks on Tuesday 11th of March 2008 12:13:27 PM
Old 03-11-2008
A handy one :-)

Code:
$ cat daysdiff.sh
D1=`date +%s -d "2007-12-19"`
D2=`date +%s -d "2008-02-09"`
((diff_sec=D2-D1))
echo - | awk -v SECS=$diff_sec '{printf "Number of days : %d",SECS/(60*60*24)}'

//Jadu
This User Gave Thanks to jaduks For This Post:
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

days elapsed between 2 dates

does anybody know how to find out the number of days elapsed between 2 dates e.g. days elapsed between 020212 and 020110 (YYMMDD format) Thanking you in advance. Ravi. (1 Reply)
Discussion started by: rkkiran
1 Replies

2. Shell Programming and Scripting

Difference between two dates in no of days ???

Hi All How to get the difference between two dates in no of days ??? My date format is like this YYYY/MM/DD. I have to get the no of days between two dates in the given format. I tried to search the forum but nothing came up similar to my requitement. Your help will be appreciated. ... (1 Reply)
Discussion started by: csaha
1 Replies

3. UNIX for Advanced & Expert Users

Number of days between two distinct dates

Hi I'm looking for a .ksh script/function that will calculate ONLY the number of days between two distinct dates. Further convert the number of days to weeks and display. I need this to be part of another larger script that checks the password expiry on several servers and notifies the... (1 Reply)
Discussion started by: radheymohan
1 Replies

4. UNIX for Dummies Questions & Answers

using 'date' to get previous days' dates

I am familiar with using the 'date' command to get the current date but I have a situation where I need to get the previous day's date as well as the date two days prior. Theoretically I could use 'expr' to compute these values but I need it to work in instances where the previous month's dates... (2 Replies)
Discussion started by: slant-40
2 Replies

5. UNIX for Dummies Questions & Answers

display all dates 200 days back

i need help! can someone help me please? i try to calculate date under unix (ksh)...AIX operating system. I have to find the date 200 days from today's date. then the script should loop 200 times and display on command line every day's date until the current date. example: todays date:... (1 Reply)
Discussion started by: pavan_test
1 Replies

6. Shell Programming and Scripting

Get number of days between given dates

Hi I need one single command to get number of days between two given dates.datecalc is not working. ex. fromdate:01.04.2010 todate :24.04.2010 i should get the out put as 23 Thanks in advance (4 Replies)
Discussion started by: suryanarayana
4 Replies

7. Shell Programming and Scripting

days are between the two dates?

I have two times in the format of YYMMDD. Does anyone know an easy way in ksh for me to display how many days are between the two dates? Example1: X=101202 Y=101205 There are 3 days between X & Y Example2: X=101202 Y=111202 There are 365 days between X & Y Example3: X=101205... (3 Replies)
Discussion started by: oldman2
3 Replies

8. UNIX for Advanced & Expert Users

How to get the sunday days between two dates?

Hi Am using Unix Ksh I have a two date input as DATE1=02/12/2012 DATE2=30/12/2012 I Need the output as only sunday date 02/12/2012 09/12/2012 16/12/2012 23/12/2012 30/12/2012 can anyone pls help me.. thanks in advance... (2 Replies)
Discussion started by: Venkatesh1
2 Replies

9. Shell Programming and Scripting

Difference in dates in days (ksh shell)

Hi Guys, Need a small help, how do i get the difference between two dates (in days) in KSH shell My date is in mm/dd/YYYY format, Is there a function to get time stamp from the respective date and time ( mm/dd/yyyy HH:MM:SS) (1 Reply)
Discussion started by: selvankj
1 Replies

10. Shell Programming and Scripting

Get number of days between 2 dates

Gents. Please can u help. I would like to calculate the days between two dates. Example file1 ( previous date) file1 - Input file 9/29/2010 10195 9/29/2010 1057 2/2/2016 10 2/2/2016 10169 2/2/2016 1057 2/3/2016 10005 2/3/2016 10014 In file2 I add the actual date using this code.... (9 Replies)
Discussion started by: jiam912
9 Replies
Image::ExifTool::Shift(3)				User Contributed Perl Documentation				 Image::ExifTool::Shift(3)

NAME
Image::ExifTool::Shift.pl - ExifTool time shifting routines DESCRIPTION
This module contains routines used by ExifTool to shift date and time values. DETAILS
Time shifts are applied to standard EXIF-formatted date/time values (ie. "2005:03:14 18:55:00"). Date-only and time-only values may also be shifted, and an optional timezone (ie. "-05:00") is also supported. Here are some general rules and examples to explain how shift strings are interpreted: Date-only values are shifted using the following formats: 'Y:M:D' - shift date by 'Y' years, 'M' months and 'D' days 'M:D' - shift months and days only 'D' - shift specified number of days Time-only values are shifted using the following formats: 'h:m:s' - shift time by 'h' hours, 'm' minutes and 's' seconds 'h:m' - shift hours and minutes only 'h' - shift specified number of hours Timezone shifts are specified in the following formats: '+h:m' - shift timezone by 'h' hours and 'm' minutes '-h:m' - negative shift of timezone hours and minutes '+h' - shift timezone hours only '-h' - negative shift of timezone hours only A valid shift value consists of one or two arguments, separated by a space. If only one is provided, it is assumed to be a time shift when applied to a time-only or a date/time value, or a date shift when applied to a date-only value. For example: '7' - shift by 1 hour if applied to a time or date/time value, or by one day if applied to a date value '2:0' - shift 2 hours (time, date/time), or 2 months (date) '5:0:0' - shift 5 hours (time, date/time), or 5 years (date) '0:0:1' - shift 1 s (time, date/time), or 1 day (date) If two arguments are given, the date shift is first, followed by the time shift: '3:0:0 0' - shift date by 3 years '0 15:30' - shift time by 15 hours and 30 minutes '1:0:0 0:0:0+5:0' - shift date by 1 year and timezone by 5 hours A date shift is simply ignored if applied to a time value or visa versa. Numbers specified in shift fields may contain a decimal point: '1.5' - 1 hour 30 minutes (time, date/time), or 1 day (date) '2.5 0' - 2 days 12 hours (date/time), 12 hours (time) or 2 days (date) And to save typing, a zero is assumed for any missing numbers: '1::' - shift by 1 hour (time, date/time) or 1 year (date) '26:: 0' - shift date by 26 years '+:30 - shift timezone by 30 minutes Below are some specific examples applied to real date and/or time values ('Dir' is the applied shift direction: '+' is positive, '-' is negative): Original Value Shift Dir Shifted Value --------------------- ------- --- --------------------- '20:30:00' '5' + '01:30:00' '2005:01:27' '5' + '2005:02:01' '11:54:00' '2.5 0' - '23:54:00' '2005:11:02' '2.5 0' - '2005:10:31' '2005:11:02 11:54:00' '2.5 0' - '2005:10:30 23:54:00' '2004:02:28 08:00:00' '1 1.3' + '2004:02:29 09:18:00' '07:00:00' '-5' + '07:00:00' '07:00:00+01:00' '-5' + '07:00:00-04:00' '07:00:00Z' '+2:30' - '07:00:00-02:30' '1970:01:01' '35::' + '2005:01:01' '2005:01:01' '400' + '2006:02:05' '10:00:00.00' '::1.33' + '09:59:58.67' NOTES
The format of the original date/time value is not changed when the time shift is applied. This means that the length of the date/time string will not change, and only the numbers in the string will be modified. The only exception to this rule is that a 'Z' timezone is changed to '+00:00' notation if a timezone shift is applied. A timezone will not be added to the date/time string. TRICKY
This module is perhaps more complicated than it needs to be because it is designed to be very flexible in the way time shifts are specified and applied... The ability to shift dates by Y years, M months, etc, is somewhat contradictory to the goal of maintaining a constant shift for all time values when applying a batch shift. This is because shifting by 1 month can be equivalent to anything from 28 to 31 days, and 1 year can be 365 or 366 days, depending on the starting date. The inconsistency is handled by shifting the first tag found with the actual specified shift, then calculating the equivalent time difference in seconds for this shift and applying this difference to subsequent tags in a batch conversion. So if it works as designed, the behaviour should be both intuitive and mathematically correct, and the user shouldn't have to worry about details such as this (in keeping with Perl's "do the right thing" philosophy). AUTHOR
Copyright 2003-2010, Phil Harvey (phil at owl.phy.queensu.ca) This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself. SEE ALSO
Image::ExifTool(3pm) perl v5.12.1 2010-01-04 Image::ExifTool::Shift(3)
All times are GMT -4. The time now is 02:58 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy