sed to replace text with a variable Post: 302173488

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find and replace text with a variable?

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LEARN ABOUT OSF1

dxmcstextreplace

DXmCSTextReplace(3X)													      DXmCSTextReplace(3X)

NAME

       DXmCSTextReplace - Replaces a specified segment of text in a compound string text widget.

SYNOPSIS

       DXmCSTextStatus DXmCSTextReplace(
	       Widget widget,
	       int from_pos,
	       int to_pos,
	       XmString value );

PARAMETERS

       The  identifier	(widget ID) of the compound string text widget.  An integer that represents the first character position of the text being
       replaced.  An integer that represents the last character position of the text being replaced.  Replacement text for  part  of  the  current
       text in the compound string text widget, or additional text to be inserted into the compound string text widget.

DESCRIPTION

       The  DXmCSTextReplace  routine  replaces  part  of  the text in the compound string text widget.  Within the widget, positions are numbered
       starting at 0 and increasing sequentially.  For example, to replace the second and third characters in the text, from_pos should be  1  and
       to_pos should be 3.  To insert text after the fourth character, from_pos and to_pos should both be 4.

RETURN VALUES

       A value that represents the status (success or failure) of the replace operation, as follows:

       --------------------------------------------------------
       Value			  Description
       --------------------------------------------------------
       DXmCSTextStatusEditDone	  Text replaced successfully.
       DXmCSTextStatusEditError   Text not replaced (failure).
       --------------------------------------------------------

SEE ALSO

       DXmCreateCSText(3X), DXmCSTextSetString(3X), DXmCSTextGetString(3X)

															      DXmCSTextReplace(3X)

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find and replace text with a variable?

Discussion started by: doublejz

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replace with value of variable using SED

Discussion started by: prvnrk

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Sed , Replace a "variable text" inside of a statement

Discussion started by: jackn7

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Replace with a variable in sed command

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