I have a script that facillitates NDM (Connect::\Direct) transfer to remote hosts. This script uses getopts to parse through the parameters passed to it and to set appropriate variables based upon what was passed in.
Kickoff="mv $PATH/$FILE1 $PATH/$FILE2"
ndm_shell.ksh -p $Node -s $Source -d... (3 Replies)
Hi,
My script will take a input file as a parameter(which is not mandatory) and also an option.
ksh my_script.sh <inputfile>
The option -n I have given is no way related to the input file.
Now the problem here is when i execute the script specifying the input file and the option(the way... (4 Replies)
Is there a restriction on levels of using 'getopts' ? I have several scripts, each of which requires an option as the first parameter .
If I call one prg separately it works fine, but when one prg calls another prg and passes the option on the called prg, then the called prg
seems not to process... (3 Replies)
Hi,
I have a program where I want to use getopts.
I want to use "-i" option and then optionally supply arguments.
If user dosent supply arguments, then also it should work.
Please tell me how to proceed.
Here is some code, this is not right code btw but a sample to understand what I want to... (1 Reply)
Hey, i need help with the use of getopts in shell script.
tried reading a lot online, but found incomplete examples (maybe complete but cudn't make out). PLzz help...explain in deatil plzzz, i am a newbie:confused: (3 Replies)
First off, I apologize for my lack of knowledge. I realize my problem will probably seem pretty basic to everyone, but I've been at this for several hours now and I've gotten nowhere. I would contact my professor, but it is too late for that.
Anyway, I'm trying to write a function called... (1 Reply)
Hi all...
I have been looking on here for the past few days for an answer and Im gonna have to break down and ask.
I just learned about the getopts command last week so have been trying to utilize it in my scripts.
Below, I am trying to set up a case structure for options using getopts.... (1 Reply)
while getopts v OPTION
do
case $OPTION in
v) echo "Hello" ;;
*) exit 1;;
esac
done
Suppose I have script tmp.sh
Whose Signature is tmp.sh <fixed_argument>
When I run the script with tmp.sh -v "file", it echoes a hello but, when I try the other way i.e, tmp.sh... (1 Reply)
Hi All,
I am writing a script to pass the getopts argument to the function which I have. But it as soon as I execute the script, the argument is taking it as blank. I tried using multiple way to check but its not working.
Can someone please let me know what wrong in this code.
function1()... (4 Replies)
Hi. Can somebody please show me an example of how to use getopts to assign a variable if it's been passed into the script but to set a default if no value has been passed in? And also how to handle a param with multiple values ... so a sub parse (can I use a function for this?)?
Here's my code... (1 Reply)
Discussion started by: user052009
1 Replies
LEARN ABOUT PHP
unset
UNSET(3) 1 UNSET(3)unset - Unset a given variableSYNOPSIS
void unset (mixed $var, [mixed $...])
DESCRIPTION unset(3) destroys the specified variables.
The behavior of unset(3) inside of a function can vary depending on what type of variable you are attempting to destroy.
If a globalized variable is unset(3) inside of a function, only the local variable is destroyed. The variable in the calling environment
will retain the same value as before unset(3) was called.
<?php
function destroy_foo()
{
global $foo;
unset($foo);
}
$foo = 'bar';
destroy_foo();
echo $foo;
?>
The above example will output:
bar
To unset(3) a global variable inside of a function, then use the $GLOBALS array to do so:
<?php
function foo()
{
unset($GLOBALS['bar']);
}
$bar = "something";
foo();
?>
If a variable that is PASSED BY REFERENCE is unset(3) inside of a function, only the local variable is destroyed. The variable in the
calling environment will retain the same value as before unset(3) was called.
<?php
function foo(&$bar)
{
unset($bar);
$bar = "blah";
}
$bar = 'something';
echo "$bar
";
foo($bar);
echo "$bar
";
?>
The above example will output:
something
something
If a static variable is unset(3) inside of a function, unset(3) destroys the variable only in the context of the rest of a function. Fol-
lowing calls will restore the previous value of a variable.
<?php
function foo()
{
static $bar;
$bar++;
echo "Before unset: $bar, ";
unset($bar);
$bar = 23;
echo "after unset: $bar
";
}
foo();
foo();
foo();
?>
The above example will output:
Before unset: 1, after unset: 23
Before unset: 2, after unset: 23
Before unset: 3, after unset: 23
PARAMETERS
o $var
- The variable to be unset.
o $...
- Another variable ...
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
unset(3) example
<?php
// destroy a single variable
unset($foo);
// destroy a single element of an array
unset($bar['quux']);
// destroy more than one variable
unset($foo1, $foo2, $foo3);
?>
Example #2
Using (unset) casting
(unset) casting is often confused with the unset(3) function. (unset) casting serves only as a NULL-type cast, for completeness. It
does not alter the variable it's casting.
<?php
$name = 'Felipe';
var_dump((unset) $name);
var_dump($name);
?>
The above example will output:
NULL
string(6) "Felipe"
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
Note
It is possible to unset even object properties visible in current context.
Note
It is not possible to unset $this inside an object method since PHP 5.
Note
When using unset(3) on inaccessible object properties, the __unset() overloading method will be called, if declared.
SEE ALSO isset(3), empty(3), __unset(), array_splice(3).
PHP Documentation Group UNSET(3)