Sponsored Content
Full Discussion: Using getopts
Top Forums Shell Programming and Scripting Using getopts Post 302173003 by jim mcnamara on Wednesday 5th of March 2008 10:05:57 AM
Old 03-05-2008
Here is an example of using multiple optional arguments. All of them are in OPTARG.
Code:
#!/bin/ksh
# foo is shell function in this example - it could be a separate script
foo()
{
	echo "foo: I got $# options"	
	echo " they are $@"
}
while getopts a:  opt
do
  set -A arr $OPTARG
  case $opt in
    a) echo "option -a"
       for i in $OPTARG
       do
           echo "subargument = $i"         
       done
       echo "running foo with these options"
       foo $OPTARG
       exit 0 ;;
   \?) echo "\nUsage: $0 [-a <option>]" >&2
        exit 2;;
  esac
done

usage:
Quote:
csadev:/home/jmcnama> t.sh -a "1 2 3 4"
option -a
subargument = 1
subargument = 2
subargument = 3
subargument = 4
running foo with these options
foo: I got 4 options
they are 1 2 3 4
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

getopts

I have a script that facillitates NDM (Connect::\Direct) transfer to remote hosts. This script uses getopts to parse through the parameters passed to it and to set appropriate variables based upon what was passed in. Kickoff="mv $PATH/$FILE1 $PATH/$FILE2" ndm_shell.ksh -p $Node -s $Source -d... (3 Replies)
Discussion started by: google
3 Replies

2. Shell Programming and Scripting

Help in getopts

Hi, My script will take a input file as a parameter(which is not mandatory) and also an option. ksh my_script.sh <inputfile> The option -n I have given is no way related to the input file. Now the problem here is when i execute the script specifying the input file and the option(the way... (4 Replies)
Discussion started by: chella
4 Replies

3. HP-UX

using getopts

Is there a restriction on levels of using 'getopts' ? I have several scripts, each of which requires an option as the first parameter . If I call one prg separately it works fine, but when one prg calls another prg and passes the option on the called prg, then the called prg seems not to process... (3 Replies)
Discussion started by: vslewis
3 Replies

4. Shell Programming and Scripting

using getopts

Hi, I have a program where I want to use getopts. I want to use "-i" option and then optionally supply arguments. If user dosent supply arguments, then also it should work. Please tell me how to proceed. Here is some code, this is not right code btw but a sample to understand what I want to... (1 Reply)
Discussion started by: som.nitk
1 Replies

5. UNIX for Dummies Questions & Answers

Getopts

Hey, i need help with the use of getopts in shell script. tried reading a lot online, but found incomplete examples (maybe complete but cudn't make out). PLzz help...explain in deatil plzzz, i am a newbie:confused: (3 Replies)
Discussion started by: SasankaBITS
3 Replies

6. Shell Programming and Scripting

getopts help

First off, I apologize for my lack of knowledge. I realize my problem will probably seem pretty basic to everyone, but I've been at this for several hours now and I've gotten nowhere. I would contact my professor, but it is too late for that. Anyway, I'm trying to write a function called... (1 Reply)
Discussion started by: Unknown50862
1 Replies

7. Shell Programming and Scripting

Using getopts. Need help

Hi all... I have been looking on here for the past few days for an answer and Im gonna have to break down and ask. I just learned about the getopts command last week so have been trying to utilize it in my scripts. Below, I am trying to set up a case structure for options using getopts.... (1 Reply)
Discussion started by: losingit
1 Replies

8. UNIX for Dummies Questions & Answers

Getopts

while getopts v OPTION do case $OPTION in v) echo "Hello" ;; *) exit 1;; esac done Suppose I have script tmp.sh Whose Signature is tmp.sh <fixed_argument> When I run the script with tmp.sh -v "file", it echoes a hello but, when I try the other way i.e, tmp.sh... (1 Reply)
Discussion started by: Devendra Hupri
1 Replies

9. Shell Programming and Scripting

Getopts help

Hi All, I am writing a script to pass the getopts argument to the function which I have. But it as soon as I execute the script, the argument is taking it as blank. I tried using multiple way to check but its not working. Can someone please let me know what wrong in this code. function1()... (4 Replies)
Discussion started by: sidh_arth85
4 Replies

10. Shell Programming and Scripting

Using getopts

Hi. Can somebody please show me an example of how to use getopts to assign a variable if it's been passed into the script but to set a default if no value has been passed in? And also how to handle a param with multiple values ... so a sub parse (can I use a function for this?)? Here's my code... (1 Reply)
Discussion started by: user052009
1 Replies
UNSET(3)								 1								  UNSET(3)

unset - Unset a given variable

SYNOPSIS
void unset (mixed $var, [mixed $...]) DESCRIPTION
unset(3) destroys the specified variables. The behavior of unset(3) inside of a function can vary depending on what type of variable you are attempting to destroy. If a globalized variable is unset(3) inside of a function, only the local variable is destroyed. The variable in the calling environment will retain the same value as before unset(3) was called. <?php function destroy_foo() { global $foo; unset($foo); } $foo = 'bar'; destroy_foo(); echo $foo; ?> The above example will output: bar To unset(3) a global variable inside of a function, then use the $GLOBALS array to do so: <?php function foo() { unset($GLOBALS['bar']); } $bar = "something"; foo(); ?> If a variable that is PASSED BY REFERENCE is unset(3) inside of a function, only the local variable is destroyed. The variable in the calling environment will retain the same value as before unset(3) was called. <?php function foo(&$bar) { unset($bar); $bar = "blah"; } $bar = 'something'; echo "$bar "; foo($bar); echo "$bar "; ?> The above example will output: something something If a static variable is unset(3) inside of a function, unset(3) destroys the variable only in the context of the rest of a function. Fol- lowing calls will restore the previous value of a variable. <?php function foo() { static $bar; $bar++; echo "Before unset: $bar, "; unset($bar); $bar = 23; echo "after unset: $bar "; } foo(); foo(); foo(); ?> The above example will output: Before unset: 1, after unset: 23 Before unset: 2, after unset: 23 Before unset: 3, after unset: 23 PARAMETERS
o $var - The variable to be unset. o $... - Another variable ... RETURN VALUES
No value is returned. EXAMPLES
Example #1 unset(3) example <?php // destroy a single variable unset($foo); // destroy a single element of an array unset($bar['quux']); // destroy more than one variable unset($foo1, $foo2, $foo3); ?> Example #2 Using (unset) casting (unset) casting is often confused with the unset(3) function. (unset) casting serves only as a NULL-type cast, for completeness. It does not alter the variable it's casting. <?php $name = 'Felipe'; var_dump((unset) $name); var_dump($name); ?> The above example will output: NULL string(6) "Felipe" NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. Note It is possible to unset even object properties visible in current context. Note It is not possible to unset $this inside an object method since PHP 5. Note When using unset(3) on inaccessible object properties, the __unset() overloading method will be called, if declared. SEE ALSO
isset(3), empty(3), __unset(), array_splice(3). PHP Documentation Group UNSET(3)
All times are GMT -4. The time now is 02:00 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy