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Full Discussion: extracting lines from a file
Top Forums UNIX for Dummies Questions & Answers extracting lines from a file Post 302172273 by ghostdog74 on Monday 3rd of March 2008 07:08:04 AM
Old 03-03-2008
Quote:
Originally Posted by trichyselva
i want to extract lines 5 and 7 from a txt file which contains nearly 20 entries how to do it
take some inspiration from here

Quote:
also i want to check whether the 42nd character is 'S' in that line
suggestions welcome
see here if you are using bash.
under "substring extraction". then check with if/else statement
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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