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Top Forums Shell Programming and Scripting grep for a particular pattern and remove few lines above top and bottom of the patter Post 302171761 by fed.linuxgossip on Friday 29th of February 2008 11:45:46 AM
Old 02-29-2008
grep for particular pattern and remove few lines above top and bottom of the pattern

grep for a particular pattern and remove 5 lines above the pattern and 6 lines below the pattern




root@server1 [~]# cat filename

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Prefix each line of output with the line number within its input file.
#######################################################################################

root@server1 [~]# grep -n "pattern_" 12345
12Smilieattern_to_remove
root@server1 [~]#




Now I want that 5 lines before line number 12 and 6 lines after line number 12 be replaced with null or removed(deleted) with a script


Please advise

Last edited by fed.linuxgossip; 02-29-2008 at 12:46 PM.. Reason: spell
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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