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Top Forums Shell Programming and Scripting grep for a particular pattern and remove few lines above top and bottom of the patter Post 302171761 by fed.linuxgossip on Friday 29th of February 2008 11:45:46 AM
Old 02-29-2008
grep for particular pattern and remove few lines above top and bottom of the pattern

grep for a particular pattern and remove 5 lines above the pattern and 6 lines below the pattern




root@server1 [~]# cat filename

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Prefix each line of output with the line number within its input file.
#######################################################################################

root@server1 [~]# grep -n "pattern_" 12345
12Smilieattern_to_remove
root@server1 [~]#




Now I want that 5 lines before line number 12 and 6 lines after line number 12 be replaced with null or removed(deleted) with a script


Please advise

Last edited by fed.linuxgossip; 02-29-2008 at 12:46 PM.. Reason: spell
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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