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Top Forums Shell Programming and Scripting Difference in day-hours-minutes-seconds format Post 302169046 by Sreejith_VK on Wednesday 20th of February 2008 05:02:21 AM
Old 02-20-2008
Difference in day-hours-minutes-seconds format

Hi experts,

I am reading two log files and passing dates as output to a txt file.
Code is given below:

echo "Start Time:" >> Report.txt
cat start.log | while read LINE1
do
echo $DATE1 >> Report.txt
done
echo "End Time:" >> Report.txt
cat end.log | while read LINE2
do
echo $DATE2 >> Report.txt
done

The out put:
Start Time:
Tue, Feb 19, 2008 08:00:02 PM
End Time:
Wed, Feb 20, 2008 02:19:09 AM

Now I want to print the overall time difference between the first output (ie $LINE1) and second output (ie $LINE2)in day-hours-minutes-seconds format.

I read the FAQs on subtracting dates, but couldnt find a method to subtract two dates in the above format.

Thanks in advance.
Sree
Sreejith_VK
 

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Time::JulianDay(3)					User Contributed Perl Documentation					Time::JulianDay(3)

NAME
Time::JulianDay -- Julian calendar manipulations SYNOPSIS
use Time::JulianDay $jd = julian_day($year, $month_1_to_12, $day) $jd = local_julian_day($seconds_since_1970); $jd = gm_julian_day($seconds_since_1970); ($year, $month_1_to_12, $day) = inverse_julian_day($jd) $dow = day_of_week($jd) print (Sun,Mon,Tue,Wed,Thu,Fri,Sat)[$dow]; $seconds_since_jan_1_1970 = jd_secondslocal($jd, $hour, $min, $sec) $seconds_since_jan_1_1970 = jd_secondsgm($jd, $hour, $min, $sec) $seconds_since_jan_1_1970 = jd_timelocal($sec,$min,$hours,$mday,$month_0_to_11,$year) $seconds_since_jan_1_1970 = jd_timegm($sec,$min,$hours,$mday,$month_0_to_11,$year) DESCRIPTION
JulianDay is a package that manipulates dates as number of days since some time a long time ago. It's easy to add and subtract time using julian days... The day_of_week returned by day_of_week() is 0 for Sunday, and 6 for Saturday and everything else is in between. ERRATA
Time::JulianDay is not a correct implementation. There are two problems. The first problem is that Time::JulianDay only works with integers. Julian Day can be fractional to represent time within a day. If you call inverse_julian_day() with a non-integer time, it will often give you an incorrect result. The second problem is that Julian Days start at noon rather than midnight. The julian_day() function returns results that are too large by 0.5. What to do about these problems is currently open for debate. I'm tempted to leave the current functions alone and add a second set with more accurate behavior. There is another implementation in Astro::Time that may be more accurate. GENESIS
Written by David Muir Sharnoff <muir@idiom.com> with help from previous work by Kurt Jaeger aka PI <zrzr0111@helpdesk.rus.uni-stuttgart.de> based on postings from: Ian Miller <ian_m@cix.compulink.co.uk>; Gary Puckering <garyp%cognos.uucp@uunet.uu.net> based on Collected Algorithms of the ACM ?; and the unknown-to-me author of Time::Local. LICENSE
Copyright (C) 1996-1999 David Muir Sharnoff. License hereby granted for anyone to use, modify or redistribute this module at their own risk. Please feed useful changes back to muir@idiom.com. perl v5.12.1 2004-02-08 Time::JulianDay(3)
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