02-20-2008
Quote:
Originally Posted by
askumarece
Jim,
Is it possible to get zero or more white spaces b4 the pattern??
Bez i have a file which looks like this.......
File Content :
---------------
package com.att.iom; line 1
[single space]package com.att.iom; line 2
[double space]package com.att.iom; line 3
package com.att.iom; line 4
something package com.att.iom;..... ##but I don't need this line line 5
[single space]package com.att.iom; line 6
something something package com.att.iom;##but I don't need this line line 7
package com.att.iom; line8
--------------------------
I need the o/p like this :
-----------------------
package com.att.iom; line 1
[single space]package com.att.iom; line 2
[double space]package com.att.iom; line 3
package com.att.iom; line 4
[single space]package com.att.iom; line 6
package com.att.iom; line8
------------------------
If it is possible then pls help me out........
thanks,
Saravana
In jim's last post, there are 5 grep solutions. Did you try using those ? One of those does what you want.
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LEARN ABOUT DEBIAN
ocamldot
OCAMLDOT(1) General Commands Manual OCAMLDOT(1)
NAME
ocamldot - generate dependency graphs of ocaml programs
SYNOPSIS
ocamldot [options] <dependency-file>
DESCRIPTION
This manual page documents briefly the ocamldot command.
ocamldot generates program dependency graphs for ocaml programs. The dependency graph output by ocamldot can be rendered by a separate
program, dot.
Ocamldot is designed to process the output of ocamldep. A typical use would be
ocamldep *.ml | ocamldot > dep.dot
or
ocamldep *.ml > .depend
ocamldot .depend > dep.dot
OPTIONS
-fullgraph
Draw the full graph (default is to draw only the kernel)
-landscape
Output in landscape format (default is portrait)
-lr Draw graph from left to right (default is top to bottom)
-r <r> Use <r> as a root in the graph; nodes reachable from <r> will be shown.
The transitive kernel of a dag is the smallest subset of the dag whose transitive closure is the same as the transitive closure of the dag.
For example, the kernel of A->B, A->C, B->C is just the two edges A->B, B->C.
SEE ALSO
ocamldep(1), dot(1)
http://www.research.att.com/~trevor/ocamldot.
AUTHOR
Trevor Jim <trevor@research.att.com>
OCAMLDOT(1)