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Full Discussion: Variable Substitution Issue
Operating Systems Solaris Variable Substitution Issue Post 302167876 by calredd on Friday 15th of February 2008 05:48:51 PM
Old 02-15-2008
Quote:
Originally Posted by fimblo
eval echo \$VAR_$TEMP

This 3-word expression goes thru the last word twice- the first iteration by eval which evaluates the expression followin it- where it expands the var $TEMP to 'ONE', and also unescapes the first backslash.

This leaves 'echo $VAR_ONE'. echo does its job, and you get:
hello.

cheers, hope this helps.

EDIT: Didnt test this in ksh now, but I think this is how I did it at work...

Thanks this solution works but I want to assign the output to a variable.... its not working. I tried both

Q=eval echo \$VAR_$TEMP
Q=`eval echo \$VAR_$TEMP`

echo $Q doesnt give same output as eval echo \$VAR_$TEMP
 

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EVAL(3) 								 1								   EVAL(3)

eval - Evaluate a string as PHP code

SYNOPSIS
mixed eval (string $code) DESCRIPTION
Evaluates the given $code as PHP. Caution The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged. If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user provided data into it without properly validating it beforehand. PARAMETERS
o $code - Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g. 'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error, whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe- cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible after it terminates. RETURN VALUES
eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to catch a parse error in eval(3) using set_error_handler(3). EXAMPLES
Example #1 eval(3) example - simple text merge <?php $string = 'cup'; $name = 'coffee'; $str = 'This is a $string with my $name in it.'; echo $str. " "; eval("$str = "$str";"); echo $str. " "; ?> The above example will output: This is a $string with my $name in it. This is a cup with my coffee in it. NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. Tip As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of this function, and save it in a string (for example). Note In case of a fatal error in the evaluated code, the whole script exits. SEE ALSO
call_user_func(3). PHP Documentation Group EVAL(3)
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