Sponsored Content
Top Forums Shell Programming and Scripting Can "sed" substitute word on a specific line? Post 302167512 by sb008 on Thursday 14th of February 2008 04:16:07 PM
Old 02-14-2008
1)

sed -e "<line number>s/<search pattern>/<replacement string>/"

e.g. replace on line 4 the word "bike" by "car"

sed -e "4s/bike/car/"

2)
sed -e "s%\(<word>\).*\(</word>\)%\1<replacement string>\2%"
% is used instead of / so the / in front of the 2nd "word" doesnt need to be escaped.

or with /
sed -e "s/\(<word>\).*\(<\/word>\)/\1<replacement string>\2/"

Last edited by sb008; 02-14-2008 at 05:29 PM..
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

sed substitute / for \ : error "Function can not be parsed"

Hello all, I have a weird issue when trying to substitute the slashes into backslashes. If I execute this on the command-line (bash / ksh) I get the path correctly translated with backslashes instead of slashes. > echo $PWD | sed 's/\//\\/g' However, when I put this in my script to... (3 Replies)
Discussion started by: candyflip2000
3 Replies

2. UNIX for Dummies Questions & Answers

Explain the line "mn_code=`env|grep "..mn"|awk -F"=" '{print $2}'`"

Hi Friends, Can any of you explain me about the below line of code? mn_code=`env|grep "..mn"|awk -F"=" '{print $2}'` Im not able to understand, what exactly it is doing :confused: Any help would be useful for me. Lokesha (4 Replies)
Discussion started by: Lokesha
4 Replies

3. Shell Programming and Scripting

How to substitute "\" by "\/" using SED?

Input: a/b/c Output required: a\/b\/c This does not work: sed s/'\/'/'\//'/g (6 Replies)
Discussion started by: indianjassi
6 Replies

4. Shell Programming and Scripting

cat $como_file | awk /^~/'{print $1","$2","$3","$4}' | sed -e 's/~//g'

hi All, cat file_name | awk /^~/'{print $1","$2","$3","$4}' | sed -e 's/~//g' Can this be done by using sed or awk alone (4 Replies)
Discussion started by: harshakusam
4 Replies

5. Shell Programming and Scripting

How do I grep with sed and substitute a "#" on that line

Hey all, I am trying to disable a certain cronjob before I run a backup. I want to be able to add/remove a "#" from the beginning on the crontab line it is located on. Here is the crontab: 46 11 * * * /etc/webmin/cron/tempdelete.pl @daily /etc/webmin/time/sync.pl */5 * * * *... (4 Replies)
Discussion started by: eg mike
4 Replies

6. Shell Programming and Scripting

awk command to replace ";" with "|" and ""|" at diferent places in line of file

Hi, I have line in input file as below: 3G_CENTRAL;INDONESIA_(M)_TELKOMSEL;SPECIAL_WORLD_GRP_7_FA_2_TELKOMSEL My expected output for line in the file must be : "1-Radon1-cMOC_deg"|"LDIndex"|"3G_CENTRAL|INDONESIA_(M)_TELKOMSEL"|LAST|"SPECIAL_WORLD_GRP_7_FA_2_TELKOMSEL" Can someone... (7 Replies)
Discussion started by: shis100
7 Replies

7. Shell Programming and Scripting

how to use "cut" or "awk" or "sed" to remove a string

logs: "/home/abc/public_html/index.php" "/home/abc/public_html/index.php" "/home/xyz/public_html/index.php" "/home/xyz/public_html/index.php" "/home/xyz/public_html/index.php" how to use "cut" or "awk" or "sed" to get the following result: abc abc xyz xyz xyz (8 Replies)
Discussion started by: timmywong
8 Replies

8. Shell Programming and Scripting

In Vi "sed" substitute word on a specific line

i need to substitute word on a specific line. I was able to do it on command line like below but it is not working in vi. command line like below: sed -e '8s/table_name/schema.table_name/' file_name. in vi table_name and schema are my positional parameters that i pass into the script. ... (5 Replies)
Discussion started by: pimmit22043
5 Replies

9. Shell Programming and Scripting

Bash script - Print an ascii file using specific font "Latin Modern Mono 12" "regular" "9"

Hello. System : opensuse leap 42.3 I have a bash script that build a text file. I would like the last command doing : print_cmd -o page-left=43 -o page-right=22 -o page-top=28 -o page-bottom=43 -o font=LatinModernMono12:regular:9 some_file.txt where : print_cmd ::= some printing... (1 Reply)
Discussion started by: jcdole
1 Replies

10. Shell Programming and Scripting

Add the word "prefix" to beginning of line using sed

SUSE linux bash shell this works test -d /tmpp && echo "directory exists" || echo "directory doesn't exists" |sed -e "s/^/prefix /" prefix directory doesn't exists but why doesn't this work? test -d /tmp && echo "directory exists" || echo "directory doesn't exists" |sed -e... (3 Replies)
Discussion started by: snoman1
3 Replies
SHTOOL-SUBST.TMP(1)					      GNU Portable Shell Tool					       SHTOOL-SUBST.TMP(1)

NAME
shtool-subst - GNU shtool sed(1) substitution operations SYNOPSIS
shtool subst [-v|--verbose] [-t|--trace] [-n|--nop] [-w|--warning] [-q|--quiet] [-s|--stealth] [-i|--interactive] [-b|--backup ext] [-e|--exec cmd] [-f|--file cmd-file] [file] [file ...] DESCRIPTION
This command applies one or more sed(1) substitution operations to stdin or any number of files. OPTIONS
The following command line options are available. -v, --verbose Display some processing information. -t, --trace Enable the output of the essential shell commands which are executed. -n, --nop No operation mode. Actual execution of the essential shell commands which would be executed is suppressed. -w, --warning Show warning on substitution operation resulting in no content change on every file. The default is to show a warning on substitution operations resulted in no content change on all files. -q, --quiet Suppress warning on substitution operation resulting in no content change. -s, --stealth Stealth operation. Preserve timestamp on file. -i, --interactive Enter interactive mode where the user has to approve each operation. -b, --backup ext Preserve backup of original file using file name extension ext. Default is to overwrite the original file. -e, --exec cmd Specify sed(1) command directly. -f, --file cmd-file Read sed(1) command from file. EXAMPLE
# shell script shtool subst -i -e 's;(c) ([0-9]*)-2000;(c) 1-2001;' *.[ch] # RPM spec-file %install shtool subst -v -n -e 's;^(prefix=).*;1 $RPM_BUILD_ROOT%{_prefix};g' -e 's;^(sysconfdir=).*;1 $RPM_BUILD_ROOT%{_prefix}/etc;g' `find . -name Makefile -print` make install HISTORY
The GNU shtool subst command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 2001 for GNU shtool. It was prompted by the need to have a uniform and convenient patching frontend to sed(1) operations in the OpenPKG package specifications. SEE ALSO
shtool(1), sed(1). 18-Jul-2008 shtool 2.0.8 SHTOOL-SUBST.TMP(1)
All times are GMT -4. The time now is 01:20 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy