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Top Forums Shell Programming and Scripting Using output to input another command Post 302167367 by joeyg on Thursday 14th of February 2008 09:03:37 AM
Old 02-14-2008
Tools Use a for loop

#! /bin/bash

for zf in *myfile*.*
do
ls -l $zf
tail $zf
done

Notes:
(1) I do an ls command; not needed - just shows what file is being looked at in the loop
(2) tail is its own command line since guess you want to do more than simply execute this one command

This could all be done in one line as:
tail *myfile*.*
but, I figure this is part of something more complicated.
So, two choices.
 

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TAIL(1) 						      General Commands Manual							   TAIL(1)

NAME
tail - deliver the last part of a file SYNOPSIS
tail [ +-number[lbc][rf] ] [ file ] tail [ -fr ] [ -n nlines ] [ -c ncharacters ] [ file ] DESCRIPTION
Tail copies the named file to the standard output beginning at a designated place. If no file is named, the standard input is copied. Copying begins at position +number measured from the beginning, or -number from the end of the input. Number is counted in lines, 1K blocks or characters, according to the appended flag or Default is -10l (ten ell). The further flag causes tail to print lines from the end of the file in reverse order; (follow) causes tail, after printing to the end, to keep watch and print further data as it appears. The second syntax is that promulgated by POSIX, where the numbers rather than the options are signed. EXAMPLES
tail file Print the last 10 lines of a file. tail +0f file Print a file, and continue to watch data accumulate as it grows. sed 10q file Print the first 10 lines of a file. SOURCE
/sys/src/cmd/tail.c BUGS
Tails relative to the end of the file are treasured up in a buffer, and thus are limited in length. According to custom, option +number counts lines from 1, and counts blocks and characters from 0. TAIL(1)
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