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Top Forums Shell Programming and Scripting Getting the lines between last occurrence of two patterns Post 302167331 by rvz on Thursday 14th of February 2008 06:03:00 AM
Old 02-14-2008
thank you very much
it is working fine
Can you explain your script for my understanding
 

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CRON(8) 						      System Manager's Manual							   CRON(8)

NAME
cron - clock daemon SYNOPSIS
auth/cron [-c] DESCRIPTION
Cron executes commands at specified dates and times according to instructions in the files /cron/user/cron. It runs only on an authentica- tion server. Option -c causes cron to create /cron/user and /cron/user/cron for the current user; it can be run from any Plan 9 machine. Blank lines and lines beginning with # in these files are ignored. Entries are lines with fields minute hour day month weekday host command Command is a string, which may contain spaces, that is passed to an rc(1) running on host for execution. The first five fields are integer patterns for minute 0-59 hour 0-23 day of month 1-31 month of year 1-12 day of week 0-6; 0=Sunday The syntax for these patterns is time : '*' | range range : number | number '-' number | range ',' range Each number must be in the appropriate range. Hyphens specify inclusive ranges of valid times; commas specify lists of valid time ranges. To run the job, cron calls host and authenticates remote execution, equivalent to running rx host command (see con(1)). The user's profile is run with $service set to rx. Cron is not a reliable service. It skips commands if it cannot reach host within two minutes, or if the cron daemon is not running at the appropriate time. EXAMPLES
Here is the job that mails system news. % cat /cron/upas/cron # send system news 15 8-17, 21 *** helix /mail/lib/mailnews % SOURCE
/sys/src/cmd/auth/cron.c SEE ALSO
con(1), rc(1) CRON(8)
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