Hi friends
I need to splict special character "|" here.
Here is my script which giving error
LINE=INVTRAN|cd /home/msgGoogle
TraxFolderType=`awk -F"|" '{print $1}' $LINE`
filePath=`awk -F"|" '{print $2}' $LINE`
echo "TraxFolderType: "$TraxFolderType
echo "filePath :"$filePath
... (3 Replies)
All I'm trying to split a string at the $ into arrays
@data:=<dataFile>
a $3.33
b $4.44
dfg $0.56
The split command I have been playing with is:
split(/\$/, @data)
which results with
a .33 b .44 dfg .56
any help with this is appreciated
/r
Rick (9 Replies)
Hi,
My input has much more lines, but few of them are below
pin(IDF) {
direction : input;
drc_pinsigtype : signal;
pin(SELDIV6) {
direction : input;
drc_pinsigtype : ... (3 Replies)
Hi Experts.
I'm stuck with the below AWK code where i'm trying to move the records containing any special characters in the last field to a bad file.
awk -F, '{if ($NF ~ /^|^/) print >"goodfile";else print >"badfile"}' filename
sample data
1,abc,def,1234,A *
2,bed,dec,342,* A ... (6 Replies)
Hello
I have string (string can have more sections)
LINE="AA;BB;CC;DD;EE"I would like to assigne each part of string separated by ";" to some new variable.
Can someone help? (4 Replies)
Hi There,
I have one requirement to remove word after character "/".
Input file is
2017-07-12|02|user1l|domain1/userl|0
2017-07-12|02|user2|domain1/user2|5
2017-07-12|02|user3|domain2/user3|0
2017-07-12|02|user4|domain1/user4|432
and require OP file is
... (2 Replies)
Hi all.
I want to use sed to remove a word that ends with "!" in the first page of a file. The word I want to remove is: "DNA!".
I have search for an answer and nothing of what I found helped me.
~faizlo (2 Replies)
Discussion started by: faizlo
2 Replies
LEARN ABOUT DEBIAN
datetime::format::epoch::activedirectory
DateTime::Format::Epoch::ActiveDirectory(3pm) User Contributed Perl Documentation DateTime::Format::Epoch::ActiveDirectory(3pm)NAME
DateTime::Format::Epoch::ActiveDirectory - Active Directory epoch seconds
SYNOPSIS
use DateTime::Format::Epoch::ActiveDirectory;
my $dt = DateTime::Format::Epoch::ActiveDirectory
->parse_datetime( 1051488000 );
DateTime::Format::Epoch::ActiveDirectory->format_datetime($dt);
# 1051488000
my $formatter = DateTime::Format::Epoch::ActiveDirectory->new();
my $dt2 = $formatter->parse_datetime( 1051488000 );
$formatter->format_datetime($dt2);
DESCRIPTION
This module can convert a DateTime object (or any object that can be converted to a DateTime object) to the number of seconds since the
epoch used in Microsoft Active Directory.
Note that this epoch is defined in the local time zone. This means that these two pieces of code will print the same number of seconds,
even though they represent two datetimes 6 hours apart:
$dt = DateTime->new( year => 2003, month => 5, day => 2,
time_zone => 'Europe/Amsterdam' );
print $formatter->format_datetime($dt);
$dt = DateTime->new( year => 2003, month => 5, day => 2,
time_zone => 'America/Chicago' );
print $formatter->format_datetime($dt);
METHODS
Most of the methods are the same as those in DateTime::Format::Epoch. The only difference is the constructor.
o new()
Constructor of the formatter/parser object. It has no parameters.
SUPPORT
Support for this module is provided via the datetime@perl.org email list. See http://lists.perl.org/ for more details.
AUTHOR
Eugene van der Pijll <pijll@gmx.net>
COPYRIGHT
Copyright (c) 2004 Eugene van der Pijll. All rights reserved. This program is free software; you can redistribute it and/or modify it
under the same terms as Perl itself.
SEE ALSO
DateTime
datetime@perl.org mailing list
perl v5.10.1 2007-12-03 DateTime::Format::Epoch::ActiveDirectory(3pm)