02-04-2008
Quote:
Originally Posted by
prashk15
Hello experts,
This might prove to be a stupid question to some of you, but I have tried to tackle it in different ways. Being new to shell scripting, I am requesting your help in coming up with an elegant solution. I am using Korn shell.
We have a directory with file names with the pattern:
abc_123
abc_456
xyz_789
I have to compare them against a prefix file to check whether the names behind the underscore are valid and consolidate them in different directories.
How do I do that?
1. Put them in different files and use diff/comm to compare. This requires multiple passes - since the consolidation is more than what I can highlight here.
2. Do something like:
FileList=$(ls -r $SOURCE_DIR) # list & sort
PrefixList=$(cat $PREFIX_FILE | sort -r)
for sFile in $sFileList
do
iDelimit=$(expr index $sFile _)
(( iDelimit -= 1 ))
sFileCmp=$(expr substr $sFile 1 $iDelimit)
for sPrefix in $sPrefixList
do
echo $sFileCmp compared with $sPrefix
if [ $sFileCmp -gt sPrefix ] # will not work, symbolic
then
continue
elif [ $sFileCmp -eq sPrefix ]
then
blPrefixValid=1
else
blPrefixValid=0
break
fi
done
3. Get valid prefixes and run through the directory each time to process files
Any help appreciated.
Thanks.
What is the criteria to separate the files?
Thanks
Nagarajan G
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LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)