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grep help, how do i rewrite this
Post 302163329 by weezybaby on Thursday 31st of January 2008 06:57:08 PM
01-31-2008
Thanks I almost got the same thing, just had some syntax issue that you have corrected . Thank you once again 
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LEARN ABOUT CENTOS
std::rel_ops
std::rel_ops(3) Library Functions Manual std::rel_ops(3) NAME
std::rel_ops - SYNOPSIS
Functions template<class _Tp > bool operator!= (const _Tp &__x, const _Tp &__y) template<class _Tp > bool operator<= (const _Tp &__x, const _Tp &__y) template<class _Tp > bool operator> (const _Tp &__x, const _Tp &__y) template<class _Tp > bool operator>= (const _Tp &__x, const _Tp &__y) Detailed Description The generated relational operators are sequestered here. Function Documentation template<class _Tp > bool std::rel_ops::operator!= (const _Tp &__x, const _Tp &__y) [inline] Defines != for arbitrary types, in terms of ==. Parameters: __x A thing. __y Another thing. Returns: __x != __y This function uses == to determine its result. Definition at line 87 of file stl_relops.h. template<class _Tp > bool std::rel_ops::operator<= (const _Tp &__x, const _Tp &__y) [inline] Defines <= for arbitrary types, in terms of <. Parameters: __x A thing. __y Another thing. Returns: __x <= __y This function uses < to determine its result. Definition at line 113 of file stl_relops.h. template<class _Tp > bool std::rel_ops::operator> (const _Tp &__x, const _Tp &__y) [inline] Defines > for arbitrary types, in terms of <. Parameters: __x A thing. __y Another thing. Returns: __x > __y This function uses < to determine its result. Definition at line 100 of file stl_relops.h. template<class _Tp > bool std::rel_ops::operator>= (const _Tp &__x, const _Tp &__y) [inline] Defines >= for arbitrary types, in terms of <. Parameters: __x A thing. __y Another thing. Returns: __x >= __y This function uses < to determine its result. Definition at line 126 of file stl_relops.h. Author Generated automatically by Doxygen for libstdc++ from the source code. libstdc++ Tue Jun 10 2014 std::rel_ops(3)