Since this site solved my problems before, I am back for more (solutions)
I down load via a script every day a file that has the same name as the file of the day before. I want to move that file to its own directory like:
/archive/jul30
How do I capture the systems date in a script an... (2 Replies)
Hi All
I was wondering what is the most efficient way to find files in the current directory(that may contain 100,000's files), that meets a certain specified file type and of a certain age.
I have experimented with the find command in unix but it also searches all sub directories. I have... (2 Replies)
Hi, I have a question, is there any way I can, when i create a directory, put the current date on it so that the directory name will be "name-current date"? just curious (3 Replies)
Hi,
Is there a way to zip the content (recursively) of a folder other then the current directory, and keep the directory structure intact?
Example:
/var/tmp/myfolder
----------------- file1
----------------- file2
----------------- folder1
------------------------ file3
Now I want... (3 Replies)
I am preparing a shell script to backup a few config files on a daily basis, with a retention of 30 days. Need some help with syntax/examples:
The shell script (running as cron) would require the following:
1. create a sub-directory within a specified (backup) directory, in the format... (3 Replies)
Hello,
I want to use the string with the current directory in my awk command.
I tried: 'pwd=system("pwd")'
but it doesn't work. can please help somebody? (2 Replies)
Hello All,
I have to write a shell script and use it in informatica. The script has to perform below actions:
The script gets executed from edw user.
Through the script, a DT folder has to be created under edw_sca user.
Is this scenario possible through a SHELL script or not.
... (2 Replies)
The awk below will create sub-directories in a directory (which is always the last line of file1, each block separated by an empty line), if the number in line 2 (always the first 6 digits in the format xx-xxxx) of file2 is found in $2 of file1. This is the current awk output.
If there is a... (0 Replies)
In the below I am trying to create a parent directory using the R_2019 line from f1 if what above it is not empty.
I then create sub-directories under each parent if there is a match between $2 of f1 and $2. Inside each sub-folder the matching paths in $3 and $4 in f2are printed. If there is no... (2 Replies)
In the below bash I am trying to ensure that all folders (represented by $folders) in a given directory are created. In the file f1 the trimmed folder will be there somewhere (will be multiple trimmed folders).
When that trimmed folder is found (represented by $S5) the the contents of $2 printed... (19 Replies)
Discussion started by: cmccabe
19 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)