I am trying to use the find command with delete in a directory . Even though i use a wil character search the find command is checking the hidden files which inturn results in error .
Can i avoid look that into the hidden files ?? I am using HP unix .
find /cv1/ -name "ite*" -mtime +14 -exec rm -f -r
HIw can modify the above command so that i exclude the hedden files or directory when searching ..
PLease let me know if is urgent
Thanks,
Arun
Check the syntax of the find command. It is missing the curly braces {} that represent the files returned by find and it should be terminated by an escaped semi-colon \;
I am not sure what you mean by hidden files or directories?
Hi. I have a script which is deleting files with a particular extension and older than 45 days.The code is:
find <path> -name "<filename_pattern>" -mtime +45 -exec rm {} \;
But the problem is that some important files are also getting deleted.To prevent this I have decide to make a dummy... (4 Replies)
Hi,
I have a filename Location.txt in a directory /abc.
Similar name file is present in its subdirectory /abc/xyz.
I want to find the file which is present only in /abc and not in /abc/xyz.
Please any1 of u can provide a quick suggestion.
Its very urgent.
Thanks,
Amol (2 Replies)
Hi All,
I was exploring find command and came across -prune option which would exclude search in a mention subdirectory.
My quesry is to search all files more that 100 MB size but exclude search in a subdirectory.
I am using below command,but somehow it is not working.
Can anybody help me... (6 Replies)
I have been searching, and cannot find an answer for this. I am trying to find all files for a user, lets call him (test001), and I want to exclude a specific directory.
Here is the command I run, it finds all files:
find / -user test001
I get this result:
> find / -user test001 ... (4 Replies)
Hi Forum,
I am using the below command to find files older than x days in a directory excluding subdirectories. From the previous forums I got to know that prune command helps us not to descend in subdirectories. Though I am using it here, not getting the desired result.
cd $dir... (8 Replies)
Find all files in the current directory only excluding hidden directories and files.
For the below command, though it's not deleting hidden files.. it is traversing through the hidden directories and listing normal which should be avoided.
`find . \( ! -name ".*" -prune \) -mtime +${n_days}... (7 Replies)
Hi All,
requirement is to find and remove the files from sub directories but it should exclude the files from parent directory.
At present i am using the below one but it finds and remove files from both parent and sub directories.
find ${PATH} -type f \( -name securitas\* -o -name \*gz... (1 Reply)
hello.
I try to print a list of files but excluding some directories and some files.
I would like to write a command for :
find "from_dir" "ignore dir1, dir2, ..." "ignore file1, file2,...." "where file are older than 2017-02-03T06:00:00"
Note that "DO_IT" is a local function in the script... (5 Replies)
Hello.
I use this command :
rsync -av --include=".*" --dry-run "$A_FULL_PATH_S" "$A_FULL_PATH_D"The data comes from the output of a find command.
And no full source directories are in use, only some files.
Source example... (2 Replies)
Discussion started by: jcdole
2 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)