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Full Discussion: for loop problem
Top Forums Shell Programming and Scripting for loop problem Post 302161620 by V3l0 on Friday 25th of January 2008 08:33:43 AM
Old 01-25-2008
Hello,

First, when you select "*log*", you don't have to select "*.log*" beacause they are already in the first selection !

Second, why "touching" the file before deleting it ?

Third, your script will be runnig with "unable to remove file xxx" beacause of the command "rm -f $filestodelete" that will delete all the files selected by "for files in (*log*|*.log*)"

So, I propose you the script :
Code:
list=$(ls *log*)

for file in $list
do
    cp $file $file.$(date +%a)
    rm -f $file
done

 

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LEARN ABOUT PHP

log1p

LOG1P(3)								 1								  LOG1P(3)

log1p - Returns log(1 + number), computed in a way that is accurate even when the value of number is close to zero

SYNOPSIS

       float log1p (float  $number)

DESCRIPTION

       log1p(3)  returns  log(1  +  $number) computed in a way that is accurate even when the value of $number is close to zero. log(3) might only
       return log(1) in this case due to lack of precision.

PARAMETERS

	      o $number
		- The argument to process

RETURN VALUES

	log(1 + $number)

CHANGELOG

       +--------+--------------------------------------------------+
       |Version |						   |
       |	|						   |
       |	|		    Description 		   |
       |	|						   |
       +--------+--------------------------------------------------+
       | 5.3.0	|						   |
       |	|						   |
       |	|  This function is now available on all platforms |
       |	|						   |
       +--------+--------------------------------------------------+
SEE ALSO

       expm1(3), log(3), log10(3).

PHP Documentation Group 														  LOG1P(3)
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