can you take input from another command and do printf?
such as
awk '{print $2,$1}' | sort -k1,1 -k2,2 | printf "%-10s,%15s"
this does not work.. but there must be a way.. please help me..
thank you. (3 Replies)
What is the output of the following program considering an x86 based parameter passing sequence where stack grows towards lower memory addresses and that arguments are evaluated from right to left:
int i=10;
int f1()
{
static int i = 15;
printf("f1:%d ", i);
return i--;
}
main()
{... (2 Replies)
Hi friends..
I am confused about awk printf option..
I have a comma separated file
88562848,21-JAN-08,2741079, -1188,-7433,TESTING
88558314,21-JAN-08,2741189, -1273,-7976,TESTING
and there is a line in my script ( written by someone else)
What is the use of command?
I guess... (10 Replies)
Hi,
I have just completed my first script (:D) and now i just need to format it with printf.
This is what I have:
#!/bin/ksh
TOTB=0
TOTF=0
TOTI=0
HOST=`hostname`
echo " FSYSTEM BLKS FREE INUSE MOUNTEDON"
df -m | grep -v ":"|grep -v Free|grep -v "/proc"| while read FSYSTEM... (2 Replies)
I am having a major problem with printf, The more I pad it, the less I see :(
The problem is in the first function, report
Am I ruining output somewhere? I wont print out the names propely, it cuts them off or deletes them completely :(
#!/bin/bash
report()
{
printf "%-10s" STUD# ... (2 Replies)
Hi,
I am using the following code to assign a count value to a variable. But I get nothing. Do you see anything wrong here.
I am new to all this.
$CTR=`remsh $m -l $MACHINES{$m} -n cat $output | grep -v sent | grep \"$input\" | sort -u | awk '{print $5}'`;
Upto sort - u it's... (2 Replies)
Hi, I have a scripting assignment for an intro to linux class and I'm really confused about how to do something seemingly simple.
I am supposed to Print the name of each file in the /data/dir16/subdir1 directory in the following format: "My name is: bin"
The desired output example looks like:... (1 Reply)
Hello,
I have some issue with qsub and the standard output : I launch a script that "echoes" the string "abc" and then executes a C program in which I print informations with the printf function ; the .o file contains "abc" but not the information displayed by printf. I also tried... (0 Replies)
The printf statement
pay_amount=$(printf "%013.3f" "$4")
working perfectly at one path(xxx/home/rsh) and showing error (printf: 216.000: invalid number) at another path(/opt/xxxx/xxxx).
what will be the reason?
thanks in advance (4 Replies)
Hi,
Could anyone explain me the logic behind the following program's output?
int main() {
printf("%d\n", printf("%d %d", 2, 2) & printf("%d %d", 2, 2));
printf("%d\n", printf("%d %d\n", 2, 2) & printf("%d %d\n", 2, 2));
}
Ans:
2 22 23
2 2
2 2
4 (2 Replies)
Discussion started by: royalibrahim
2 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)